3 years ago

How old does an individual need to be in the United states to purchase any tobacco products

Physics

1 answer:

erica [24]3 years ago

8 0

Answer: 18 years of age

Explanation:

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A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in

Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

for the first one: 

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

for the second one :

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

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4 years ago

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What means of motion

ki77a [65]

Power of movement of a person place or thing

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4 years ago

Plot a graph based on the passage

Mnenie [13.5K]

Hence, the horizontal velocity of the rover is 1.73 m/s

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3 years ago

If I fell asleep at 9:42 pm and woke up at 10:06 am. What was the total hours of sleep I got?

gladu [14]

Answer:

11 hours and 24 minutes total of sleep. Nice.

Explanation:

Since its going from pm to am, We have to go past 12 to 1 and go to 9 hours am, then add 42 by 24 minutes to get to the 6 minutes past 10.

#teamtrees #WAP (Water And Plant)

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3 years ago

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A conducting loop of radius 1.50 cm and resistance 8 × 10−6Ω is perpendicular to a uniform magnetic field of magnitude 23.0 × 10

Anika [276]

To solve this problem it is necessary to apply the concepts related to electromotive force or induced voltage.

By definition we know that the induced emf in the loop is equal to the negative of the change in the magnetic field, that is,

$\epsilon = -A \times \frac{\Delta B}{\Delta t}$

$\epsilon = -A \times (\frac{B_f-B_i}{t_f-t_i})$

Where A is the area of the loop, B the magnetic field and t the time.

Replacing with our values we have that

$\epsilon = -(\pi (1.5*10^{-2})^2)(\frac{0-23*10^{-6}}{7*10^{-3}-0})$

$\epsilon = 2.3225*10^{-6}V$

Therefore the thermal energy produced is given by

$E = P*t = \frac{\epsilon^2}{R}t$

$E = \frac{(2.3225*10^{-6})^2}{8*10^{-6}}*(7*10^{-3})$

$E = 4.719*10^{-9}J$

The thermal energy produced in the loop is $4.719*10^{-9}J$

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3 years ago