Answer:
The velocity of block B when the energy stored in the spring bumpers is max = 2.5m/s
Explanation:
An head on collision is aka elastic collision and in elastic collision momentum and energy is conserved that is the total momentum before collision = total momentum after collision
Given
Mass of block A mA = 3kg, initial Velocity of block A vA1 = 5m/s, Final velocity = vA2
Mass of block B mB = 9kg, Initial velocity of block B vB1 = 0m/s, Final velocity = vB2
Therefore we have the equation
1)mAvA1 + mBvB1 = mAvA2 + mBvB2
Also in elastic collision between 2 objects, the relative velocities before and after the collision have the same magnitude but opposite direction
vA1 - vB1 = vB2 - vA2
vA2 = vB2 - vA1 when vB1 = 0
Substitute into the equation we have
(3*5)+(9*0) = 3*(vB2-vA1) + (9*vB2)
15 = 3vB2 - 3vA1 +9vB2
15=3vB2 - (3*5) + 9vB2
15+15 = 12vB2
vB2 = 2.5m/s
Answer:
D(11) = 37.660 m
dD/dt = 2.7260 m/s
Explanation:
given data
two path apart = 17 m
walks east one path = 4 km/h = 1.111 m/s
walks west other path = 7 km/h = 1.944 m/s
pass each other time t = 0
solution
we consider here east is the positive direction and west is the negative direction
so that
the east - west distance between them is = 1.111 + 1.944 = 3.055 m/s
and
the actual distance between them time t is
D(t) =
at time 11 s
D(11) =
D(11) = 37.660 m
and
increase rate is dD/dt
dD/dt =
so for 11 sec
dD/dt =
dD/dt = 2.7260 m/s
Answer: initially the packet was ascending up with the balloon.
Taking upward as positive direction;
initial velocity, u = 4.9 m/s
final velocity = v m/s
initial height, h₁ = 245 m
final height, h₂ = 0
a = -9.8 m/s²
time taken = t seconds
s = ut + 0.5at²
⇒ (h₂-h₁) = ut + 0.5at²
⇒ 0-245 = 4.9t + 0.5×(-9.8)×t²
⇒ -245 = 4.9t - 4.9t²
⇒ 4.9t² -4.9t -245 =0
Solving it, we get t = 7.59s
v = u + at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/s
So velocity is 69.48 m/s downward
Explanation:
The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.