Supplement of 108 degrees
2 answers:
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See the attached figure to better understand the problem
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad
we know that
tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft
the answer is
the man is 198.45 ft from the helicopter landing pad