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kotykmax [81]
3 years ago
13

There are 22 animals in the barn. Some are ducks and some are oxen. There are 72 legs in all.

Mathematics
1 answer:
xeze [42]3 years ago
7 0

Answer:

  • 14 oxen
  • 8 ducks

Step-by-step explanation:

Let x represent the number of oxen. Then the number of ducks is 22-x and the number of legs is ...

  4x +2(22 -x) = 72

  2x +44 = 72 . . . . . . . simplify

  x +22 = 36 . . . . . . divide by 2

  x = 14 . . . . . . . . . subtract 22; the number of oxen

  22-x = 8 . . . . . the number of ducks

There are 8 ducks and 14 oxen in the barn.

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The perimeter of a playing field for a certain sport is 178 ft. The field is a rectangle, and the length is 43 ft longer than th
timofeeve [1]

Answer:

23 and 66 are the dimensions

Step-by-step explanation:

178/2=89

89+43=132

178-132=46

132/2=66

46/2=23

(I think this is the answer I'm so sorry if I am wrong)

5 0
3 years ago
A local hamburger shop sold a combined total of 659 hamburgers and cheeseburgers on Sunday. There were 50 fewer cheeseburgers so
NISA [10]

Answer:

The sold 354.5 hamburgers and 300.5 cheeseburgers.

Step-by-step explanation:

Let number of hamburgers=h

Let number of cheeseburgers=c

On Sunday, the shop sold a combined total of 659 hamburgers and cheeseburgers. Therefore:

h+c=659....(I)

There were 50 fewer cheeseburgers sold than hamburgers .

c=h-50.....(ii)

Substitution of equation (ii) into (I)

h+(h-50)=659

2h=659+50

2h=709

h=709/2=354.5

From (ii)

c=h-50

=354.5-50=300.5

The sold 354.5 hamburgers and 300.5 cheeseburgers.

NOTE: These result are from the given data. However, we were not informed if the shop sells half burgers or not

7 0
3 years ago
PLEASEEEEE HELPPPPP!! I will give Brainliest
dmitriy555 [2]
I believe it is A
Because his initial starting point is 12 and then 1.5x to increase and reach his goal of 26
8 0
3 years ago
Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event
bekas [8.4K]

Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

P(A|B) = P(A)

P(B|A) = P(B)

And for this special case we want to find this probability:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

7 0
3 years ago
Describe the possible side lengths of the 3rd side of the triangle given the lengths of the 2 other sides?
Sindrei [870]
Heya !

Using a theoram about triangles ,

Given a triangle ∆ABC, the sum of the lengths of any two sides of the triangle is greater than the length of the third side ,

Also , the length of third side always greater than absolute difference of the other two sides ,

Let the third side be x ,

So , x < 9 + 8 and x > 9 - 8
x < 17 and x > 1

Hence , x ∈ [ 2 , 17 ] inch.

Above case is true for any triangle , be it scalene , Isosceles , Right-angled ...

As , for Isosceles , the third side can be 8 or 9 inches ,
For scalene , all values in the above range satusfies ,

For right angled triangle , we have 2 cases ,

Case 1 : Third side is the hypotenuse
Then , x = √(9²+8²) = √145 = 12.0415 inch.

Case 2 : Third side is not the hypotenuse
Then , x = √(9²-8²) = √17 = 4.1231 inch.

Hope it helps you ! :)
8 0
4 years ago
Read 2 more answers
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