Lines are parallel
(Use desmos calculator for these problems)
Answer:
Step-by-step explanation:
Its the fourth choice, 8000 is closer to 8132 so you would round that down instead of choosing 8500. Also, 8000 ÷ 20 = 400
Answer:
H0 : μN ≤ μD
H1 : μN > μD
Right tailed
Test statistic = 1.33
Pvalue = 0.097
Fail to reject the Null
Step-by-step explanation:
H0 : μN ≤ μD
H1 : μN > μD
The test is right tailed ; culled from the direction of the greater than sign ">"
Night students :
n1 =30 x1= 3.34 s1 = 0.02
Day students:
n2 = 30 x2 = 3.32 s2 = 0.08
The test statistic :
(x1 - x2) / √(s1²/n1) + (s2²/n2)
T= (3.34 - 3.32) / √(0.02²/30) + (0.08²/30)
T = 0.02 / 0.0150554
Test statistic = 1.328
Using the conservative approach ;
df = Smaller of n1 - 1 or n2 - 1
df = 30 - 1 = 29
Pvalue(1.328, 29) = 0.097
At α = 0.10
Pvalue < α ; Hence, we reject H0 ; and conclude that there is significant evidence that GPA of night student is greater than GPA of day student
Answer:
6.53 s
Step-by-step explanation:
The height of the cannon ball is represented by a quadratic function as:
h(t) = -4.9t² + 30.5t +9.8.
At 0 s (i.e. t = 0), h(0) = -4.9(0²) + 30.5(0) + 9.8 = 9.8
That means that the cannon ball is initially at a height of 9.8 m above the ground. To calculate the time it takes the ball to touch the ground, we use:
h(t) = -4.9t² + 30.5t +9.8
It touches the ground when h(t) = 0. Hence:
0 = -4.9t² + 30.5t + 9.8
Solving the above quadratic equation gives:
t = 6.53 s and t = -0.31 s
Since the time cannot be negative, hence t = 6.53 s. Therefore it takes the ball 6.53 s to hit the ground.
Answer:
(1/3) Pi r^2 h
Step-by-step explanation:
The volume of a cone (or pyramid, for that matter) is 1/3 the area of the base times the height.
Cones have bases that are circles, so their areas are Pi r^2, usually written
, Pi times the radius squared.
![V=\frac{1}{3}\pi r^2h](https://tex.z-dn.net/?f=V%3D%5Cfrac%7B1%7D%7B3%7D%5Cpi%20r%5E2h)