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Vinvika [58]
2 years ago
14

12x-3y=-3 6x+y=1Solving systems​ of equations

Mathematics
2 answers:
SpyIntel [72]2 years ago
6 0

12x - 3y =  - 3 \\ 6x + y = 1

Solve the second equation for y

12x - 3y =  - 3 \\ y = 1 - 6x

Substitute the given value of y into the first equation

12x - 3(1 - 6x) =  - 3

Distribute -3 through the parentheses

12x - 3 + 18x =  - 3

Cancel equal terms on both sides of the equation

12x + 18x = 0

Collect like terms then divide both sides of equation by 30

x = 0

Substitute the given value of x into the equation y=1-6x

y = 1 - 6 \times 0

Solve for y

y = 1

The possible solution of the system is the ordered pair (x,y)

(x,y) = (0,1)

Nana76 [90]2 years ago
5 0
The answer and the process is shown in the following picture

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Jill earned 40$ from a carpool plus 9$ per hour (h) babysitting this week. turn into an Expression
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Answer:

9h + 40

Step-by-step explanation:

You use 9h, because you don't know how many hours Jill worked, she already had 40$ so 40 is the constant.

7 0
3 years ago
0.5,1/5,0.35,12/25,4/5 least to greatest
kykrilka [37]
First make sure that the divider is the same

5/10     ,   1/5       ,   35/100     , 12/25      , 4/5

50/100   ,  20/100 . 35/100     ,   48/100 , 80/100

So the least to greatest would be :
1/5   , 12/25  , 0.5  ,  4/5

Hope this helps
3 0
4 years ago
Help me my future depends on it
pshichka [43]

Answer:

Step-by-step explanation:

3 0
3 years ago
A man buys a cycle for $1400 and sells it at a loss of 15%. What is the selling price of the cycle?
Aneli [31]

Answer:

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Step-by-step explanation:

1400 - 15% to get the answer.

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6 0
3 years ago
Read 2 more answers
If you choose two cards at random from a deck of 52 cards, what is the probability that it is two diamonds?
kari74 [83]
<h3>Answer:</h3>

1/17 or 0.0588 (without replacement)

<h3>Step-by-step explanation:</h3>

To answer this question we need to know the following about a deck of cards

  • A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
  • Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
  • Additionally, there are 13 cards  in each suit (Clubs/Spades are black, Hearts/Diamonds are red) .

In this case, we are required to determine the probability of choosing two diamonds.

  • There are 13 diamonds in the deck.
  • Assuming, the cards were chosen without replacement;

P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)

P(First card is diamond) = 13/52

If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.

Therefore;

P(Second card is diamond) = 12/51

Thus;

P(Both cards are diamonds) = 13/52 × 12/51

                                               = 156/2652

                                              = 1/17 or 0.0588

Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.

5 0
4 years ago
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