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1 year ago

If a driver takes 30 min to get to the town market, which is 1.5 km away from his house, what is his average speed?

Chemistry

2 answers:

zvonat [6]1 year ago

8 0

Answer: 0.83 m/s

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

alexira [117]1 year ago

3 0

Distance divided by time
Turn 30min to seconds (divided by 60)
1.5km/h: 0.5s =3km/h

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A chemistry student combines 23.0 grams of sodium and 71.0 grams of chloride to form sodium chloride. According to the law of co

Diano4ka-milaya [45]

Answer:

94.0 g.

Explanation:

Hello!

In this case, since the lay of conservation of mass states that energy cannot be neither created nor destroyed, during a chemical reaction it is seen that the reactions undergo a change by which bonds can be broken or formed depending on the case. Thus, for the formation of sodium chloride we evidence the formation of the Na-Cl bond which means sodium is combined with chlorine according to the following chemical reaction:

$2Na(s)+Cl_2(g)\rightarrow 2NaCl(s)$

It means that the reuslting mass of product is:

$m_{NaCl}=23.0+71.0g=94.0g$

Best regards!

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2 years ago

Which process causes Earth's surface to warm?

Romashka [77]

Answer:

its B

Explanation:

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2 years ago

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For the equilibrium

sleet_krkn [62]

Answer:

$\large \boxed{\text{0.091 atm }}$

Explanation:

The balanced equation is

I₂(g) + Br₂(g) ⇌ 2IBr(g)

Data:

Kc = 8.50 × 10⁻³

n(IBr) = 0.0600 mol

V = 1.0 L

1. Calculate [IBr]

$\text{[IBr]} = \dfrac{\text{0.0600 mol}}{\text{1.0 L}} = \text{0.0600 mol/L}$

2. Set up an ICE table.

$\begin{array}{ccccccc}\rm \text{I}_{2}& + & \text{Br}_{2} & \, \rightleftharpoons \, & \text{2IBr} & & \\0 & & 0 & &0.0600 & & \\+x & & +x & &- 2x & & \\x & & x & & 0.0600 - 2x & & \\\end{array}$

3. Calculate [I₂]

$\begin{array}{rcl}K_{\text{c}}&=&\dfrac{\text{[IBr]}^{2}} {\text{[I$_{2}$][Br]$_{2}$}}\\\\8.50 \times 10^{-2}&=&{\dfrac{(0.0600 - 2x)^{2}}{x^{2}}}& &\\\\0.2915x & = &{\dfrac{0.0600 - 2x}{x}}& &\\\\0.2915x & = &0.0600 - 2x\\\\2.2915x & = & 0.0600\\x & = & \textbf{0.026 18 mol/L}\\\end{array}\\$

4. Convert the temperature to kelvins

T = (150 + 273.15) K = 423.15 K

5. Calculate p(I₂)

$\begin{array}{rcl}\\pV & = & nRT\\p & = & cRT\\p & = & \text{0.026 18 mol} \cdot \text{L}^{-1}\times \text{0.082 06 L} \cdot \text{atm} \cdot \text{K}^{-1} \text{mol}^{-1} \times \text{423.15 K}\\& = & \textbf{0.91 atm}\\\end{array}\\\text{The partial pressure of iodine is $\large \boxed{\textbf{0.91 atm}}$}$