4FeS2 + 11O2 = 2Fe2O3 + 8SO2

Percent yield is calculated as the actual yield divided by the theoretical yield multiplied by 100.

Actual yield = 55 g ( 1 mol / 159.69 g ) = 0.34 mol Fe2O3

To find for the theoretical yield, we first determine the limiting reactant.

100 g O2 ( 1 mol / 32 g) = 3.13 mol O2
200 g FeS2 (1 mol / 119.98g) = 1.67 mol FeS2

Therefore, the limiting reactant is O2.

Theoretical yield = 3.13 mol O2 ( 2 mol Fe2O3 / 11 mol O2 ) = 0.57 mol Fe2O3

Percent yield = (0.34 mol / 0.57 mol) x 100 = 59.74%

3 0

3 years ago

Would it be C???...idk HELP

givi [52]

Answer:

C. Butanal , is the aldehyde

Explanation:

A . It is carboxylic acid : ---COOH group

B. It is Ester : ----COOR group , Here R = CH3

C. It is Aldehyde : -----CHO group

D. It is ketone : ----C=O group

See image :

8 0

3 years ago

If the change in Gibbs free energy for a process is positive, the corresponding change in entropy for the universe will be

Gnesinka [82]

If the change in Gibbs free energy for a process is positive, the corresponding change in entropy for the universe will be positive.

<h3>What is Gibbs free energy?</h3>

This is defined as the energy used by a substance involved in a chemical reaction.

The Gibbs free energy and entropy has a direct relationship which is why a positive gibbs free energy will result in a corresponding positive entropy.

Read more about Gibbs free energy here brainly.com/question/9179942

4 0

2 years ago

Which of the following compounds are polar: CH2Cl2, HBr?

Olegator [25]

Answer : HBr polar

please add me to brainalist

8 0

3 years ago