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Marianna [84]
2 years ago
15

Find the cosine of ∠J.

Mathematics
1 answer:
frozen [14]2 years ago
7 0

Answer:

√94

Step-by-step explanation:

i think that is the answer

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A toy store worker packed two boxes of identical dolls and plush toys for shipping in boxes that weigh 1oz when empty. One box h
Vilka [71]
The total weight of 4 dolls and 3 plush toys is 11 oz

Let's say the dolls weigh 2 oz and the plush toys weigh 1 oz

2-4= 8 1x3 =3

8+3=11

Then 2 dolls =4 and 3 plush toys= 3

Weight should be 7oz

Plus the weight of the box 1

Total= 8 not 10
8 0
3 years ago
Solve for f.<br>-f + 2 + 4f = 8 - 3<br>f=​
Svet_ta [14]

Answer:

1

Step-by-step explanation:

-f + 2 + 4f = 8 - 3

3f = 6 - 3

3f = 3

f = 1

4 0
3 years ago
Read 2 more answers
Give an example of each of the following or explain why you think such a set could not exist.
Oksanka [162]

Answer:

a.No

b.No

c.No

Step-by-step explanation:

a.No,Such set does not exist .A set of natural numbers is N

Every point of this set is an isolated point but no accumulation point

Accumulation point:It is defined as that point a of set Swhich every neighborhood contains infinitely many distinct point of set

(a-\epsilon,e+\epsilon)\cap S-{a}\neq\phi

Isolated point : it is defined as that point a of set S which neighborhood   does not contain any other point of set except itself

(a-\epsilon0,a+\epsilon)\cap S-{a}=\phi

Interior point of set :Let a\in S .Then a is called interior point of set when its neighborhood is a subset of set S.

a\in(a-\epsilon,e+\epsilon)\subset S

When a set is uncountable then interior point exist it is  necessary for interior points existance .

Boundary points :Let a\in S .If every non empty neighborhood of a  intersect S and complement of S.

Every member of  a set is a boundary point

b.No, such set does not exist .A non empty set with isolated point then the set have no interior points .By definition of interior point and isolated point .For example.set of natural numbers

c.No, Such set does not exist ,for example set of natural every point is an isolated point and boundary point.By definition of  boundary point and isolated point

6 0
3 years ago
Please answer I have a freaking e in my math class​
sp2606 [1]

Answer: I would answer but the image is blocked for me- can you type the problem by any chance?

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
CAN I GET SOMEONES HELP ASAP!!
PIT_PIT [208]
The answer would be <QRZ

Since you are looking for an angle congruent to <UQR using the alternate interior angles theorem, interior suggests that the angle must be inside the parallel lines, se we can get rid of options <WRT and <TRZ since they are exterior angles

Furthermore, in the alternate interior angles theorem, the two angles must be alternate or opposite of each other which would show that the only possible answer would be <QRZ

hope this helped!


7 0
3 years ago
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