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solmaris [256]
2 years ago
9

Compute $\sqrt{\sqrt{256}}$. I need it quick! Thanks :)

Mathematics
2 answers:
AlekseyPX2 years ago
6 0

<u>Explanation:</u>

  • To obtain a whole number from square roots, the number inside the root must be a perfect square.
  • If you are finding a number's cube root, it means that a number must be multiplied 3 times to obtain that number.
  • It is the same with \sqrt[4]{x} (Where x is the number).

<u>Solution:</u>

  • => \sqrt{\sqrt{256}}$ = \sqrt[4]{256}
  • => \sqrt[4]{256} = \sqrt[4]{(4)(4)(4)(4)}
  • => \sqrt[4]{(4)(4)(4)(4)} = 4

Hence, \sqrt{\sqrt{256}}$ is 4.

LuckyWell [14K]2 years ago
4 0

Answer:

4

Step-by-step explanation:

16x16=256

(256/16)/16=4

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A researcher was interested in comparing the resting pulse rates of people who exercise regularly and people who do not exercise
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Answer:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, we failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

Step-by-step explanation:

Refer to the attached data.

The Null and Alternate hypothesis is given by

Null hypotheses = H₀: μ₁ = μ₂

Alternate hypotheses = H₁: μ₁ ≠ μ₂

The test statistic is given by

$ t = \frac{\bar{x}_1  - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }  $

Where \bar{x}_1 is the sample mean of people who do not exercise regularly.

Where \bar{x}_2 is the sample mean of people who do exercise regularly.

Where s_1 is the sample standard deviation of people who do not exercise regularly.

Where s_2 is the sample standard deviation of people who do exercise regularly.

Where n_1 is the sample size of people who do not exercise regularly.

Where n_2 is the sample size of people who do exercise regularly.

$ t = \frac{72.7  - 69.7}{\sqrt{\frac{10.9^2}{16} + \frac{8.2^2}{12} } }  $

t = 0.83

The given level of significance is

1 - 0.95 = 0.05

The degree of freedom is

df = 16 + 12 - 2 = 26

From the t-table, df = 26 and significance level 0.05,

t = 2.056 (two-tailed)

Conclusion:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, We failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

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Answer:

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Step-by-step explanation:

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If I need 3600 pennies and I make 2 pennie’s per 5 minutes how long would it take to get 3600
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Step-by-step explanation:

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Step-by-step explanation:

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