Complete question:
if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.
Answer:
The mutual force between the two point charges is 319.64 N
Explanation:
Given;
distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m
value of the charges, q₁ and q₂ = 2 μC and - μ4 C
Apply Coulomb's law;

where;
F is the force of attraction between the two charges
|q₁| and |q₂| are the magnitude of the two charges
r is the distance between the two charges
k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

Therefore, the mutual force between the two point charges is 319.64 N
Explanation:
The matter passes in the directions of the noise and flows from the source to a receiver like sound flows through a substance. As the sound flows through a fluid, the material is disrupted for an amount of time, but after the sound leaves, it restored to its normal location.
The answer is 4.05 × 10³ kg
The density (D) is a quotient of mass (m) and volume (V) of a substance:
D = m/V
Step 1. Calculate the volume o
We have:
D = 2.70 × 10³ kg/m³
V = 1.50 m³
m = ?
D = m/V
m = D * V
m = 2.70 × 10³ kg/m³ × 1.50 m³ = 4.05 × 10³ kg
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