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3 years ago

Five resistors are connected in a circuit as shown. Find the ammeter

Physics

1 answer:

bogdanovich [222]3 years ago

5 0

Given data states the 5 resistors connected with the value,
= 3 Ω; = 3 Ω ; = 3 Ω; = 0.5 Ω and = 0.5 Ω.
As shown, the and are in series connection, therefore,
R' = = 3 + 3 = 6 Ω
And then R' and are now in parallel connection, thereby

Ω
And then R'' with and are in series, thereby
Total

Ω.
Therefore,
Current
=1 Ampere.

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Two children are pulling on opposite sides of a blanket. The brother is pulling with a force of 3 N. The sister is pulling with

Citrus2011 [14]

Let F1=Force exerted by the brother (+F1)
F1= Force exerted by the sister (-F2)

Fnet=(+F1) + (-F2)
Fnet= (+F1) + (-F2)
Fnet=F1 - F2
Fnet= (+3N)+(-5N)
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7 0

2 years ago

Suppose that we use a heater to boil liquid nitrogen (N2 molecules). 4480 J of heat turns 20 g of liquid nitrogen into gas. Note

love history [14]

Answer:

The energy is $9.4\times10^{-21}\ J$

(a) is correct option

Explanation:

Given that,

Energy = 4480 j

Weight of nitrogen = 20 g

Boil temperature = 77 K

Pressure = 1 atm

We need to calculate the internal energy

Using first law of thermodynamics

$Q=\Delta U+W$

$Q=\Delta U+nRT$

Put the value into the formula

$4480=\Delta U+\dfrac{20}{28}\times8.314\times77$

$\Delta U=4480-\dfrac{20}{28}\times8.314\times77$

$\Delta U=4022.73\ J$

We need to calculate the number of molecules in 20 g N₂

Using formula of number of molecules

$N=n\times \text{Avogadro number}$

Put the value into the formula

$N=\dfrac{20}{28}\times6.02\times10^{23}$

$N=4.3\times10^{23}$

We need to calculate the energy

Using formula of energy

$E=\dfrac{\Delta U}{N}$

Put the value into the formula

$E=\dfrac{4022.73}{4.3\times10^{23}}$

$E=9.4\times10^{-21}\ J$

Hence, The energy is $9.4\times10^{-21}\ J$

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3 years ago

People with good hearing can perceive sounds as low in level as −7.53 dB at a frequency of 3000 Hz. What is the intensity of thi

lora16 [44]

Answer:

attached below

Explanation:

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3 years ago

which changes of state should she place in the column titled "lose energy"?freezing, boiling, and meltingmelting, vaporization,

Blababa [14]

Freezing (liquid to solid)
Deposition (gas to solid)
Condensation (gas to liquid)

All three of these state changes are a result of a energy loss. When considering energy loss it is best to think of situations where temperature has dropped. Less energy in the system results in less energy the substance is exposed to or has available.

7 0

2 years ago

Read 2 more answers

5. If a spring with a 40 N/m spring constant is used to push a 10 kg ball to a speed of 2 m/s,

kolbaska11 [484]

By compressing the spring a distance x (in m), you are storing 1/2 k x ² (in J) of potential energy, which is converted completely into kinetic energy 1/2 m v ², where

• k = 40 N/m = spring constant

• m = 10 kg = mass of the ball

• v = 2 m/s = ball's speed (at the moment the spring returns to its equilibrium point)

So we have

1/2 k x ² = 1/2 m v ²

x = √(m/k v ²) = √((10 kg) / (40 N/m) (2 m/s)²) = 1 m

3 0

3 years ago