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3 years ago

Five resistors are connected in a circuit as shown. Find the ammeter

Physics

1 answer:

bogdanovich [222]3 years ago

5 0

Given data states the 5 resistors connected with the value,
= 3 Ω; = 3 Ω ; = 3 Ω; = 0.5 Ω and = 0.5 Ω.
As shown, the and are in series connection, therefore,
R' = = 3 + 3 = 6 Ω
And then R' and are now in parallel connection, thereby

Ω
And then R'' with and are in series, thereby
Total

Ω.
Therefore,
Current
=1 Ampere.

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3 years ago

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A car was traveling at 20m/s and slammed on the brakes causing the car to decelerate at a rate of -2.5 m/s^2 before coming to a

Taya2010 [7]

Answer: 160 m

Explanation: First find time or t using the formula for acceleration:

a = vf - vi / t

So t is equal to:

t = vf - vi / a

= 0 m/s - 20 m/s / -2.5 m/s²

= 8 s

To find the distance use the formula for velocity:

v = d / t

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d = v x t

= 20 m/s x 8 s

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3 years ago

If you are driving 90 km/hkm/h along a straight road and you look to the side for 2.2 ss , how far do you travel during this ina

ICE Princess25 [194]

Answer: 55m

Explanation:

Given the following :

Driving speed = 90km/hr

Inattentive period (time) = 2.2s

Distance during inattentive period =

(driving speed * time)

Converting driving speed from km/hr to m/s

1000m = 1km

3600s = 1hour

Therefore,

90km/hr = (90 * 1000) / 3600

90km/hr = (90000)/ 3600 = 25m/s

Therefore ;

Distance during inattentive period =

(driving speed * time)

Distance during inattentive period = (25m/s × 2.2s) = 55m

Distance traveled during inattentive period is 55m

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3 years ago

Which of the following phases has a variable volume?

hram777 [196]

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4 years ago

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Wilma I. Ball walks at a constant speed of 5.93 m/s along a straight line from point A to point B and then back from B to A at a

rosijanka [135]

Answer:

Case:1 a) average speed $v_{avg}=4.1144\ m.s^{-1}$

Since the body returns to its initial position hence the displacement is zero so velocity is also zero.

CASE: 2 a) average speed $v_{avg}=3.7093\ m.s^{-1}$

Since the body returns to its initial position hence the displacement is zero so velocity is also zero.

Explanation:

Given:

Case: 1

speed of Wilma from point A to B, $v_{ab}=5.93\ m.s^{-1}$

speed of Wilma from point B to A, $v_{ba}=3.15\ m.s^{-1}$

Let the displacement from A to B be x meter.

Then the total displacement = 2x meter

time taken in going from A to B:

$t_{ab}=\frac{x}{5.93}\ s$

time taken in going from B to A:

$t_{ba}=\frac{x}{3.15} \ s$

Wilma's average speed over the entire trip:

$v_{avg}=\frac{2x}{t_{ab}+t_{ba}}$

$v_{avg}=2x\div (\frac{x}{5.93}+\frac{x}{3.15})$

$v_{avg}=4.1144\ m.s^{-1}$

Since the body returns to its initial position hence the displacement is zero so velocity is also zero.

CASE: 2

speed of Wilma from point A to B, $v_{ab}=4.51\ m.s^{-1}$

speed of Wilma from point B to A, $v_{ba}=3.15\ m.s^{-1}$

Let the displacement from A to B be x meter.

Then the total displacement = 2x meter

time taken in going from A to B:

$t_{ab}=\frac{x}{4.51}\ s$

time taken in going from B to A:

$t_{ba}=\frac{x}{3.15} \ s$

Wilma's average speed over the entire trip:

$v_{avg}=\frac{2x}{t_{ab}+t_{ba}}$

$v_{avg}=2x\div (\frac{x}{4.51}+\frac{x}{3.15})$

$v_{avg}=3.7093\ m.s^{-1}$

Since the body returns to its initial position hence the displacement is zero so velocity is also zero.

3 0

3 years ago