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liubo4ka [24]
3 years ago
9

What is the total work required to stop an 85.0 kg football halfback moving at 4.50 m/s?

Physics
1 answer:
Solnce55 [7]3 years ago
6 0

Answer:

the answer is b

Explanation:

because i said so

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Transition
Snezhnost [94]
Frozen water has move volume than water in liquid form
8 0
3 years ago
A student releases a small cart at the top of an incline with height H above the floor. The cart experiences very little frictio
Triss [41]

Answer:

Explanation:

In the whole process , potential energy of the cart is converted into kinetic energy . At the top of the vertical loop , the whole of potential energy is regained and kinetic energy becomes zero if we release the cart from a height of 2R because difference of height between lowest and highest point of motion  is 2R .  In that case kinetic energy at top = 0 , velocity v = 0

At the top , weight mg is acting which is providing centripetal force . So cart must have some velocity at the top . If it be v

mv²/R = mg

v = √ gR .

For that purpose , the cart must be released from a height greater than 2R .

The extra height beyond 2R will make the velocity at the top non-zero.

3 0
3 years ago
A 25 pF parallel-plate capacitor with an air gap between the plates is connected to a 100 V battery. A Teflon slab is then inser
fgiga [73]

Answer:

5.3 nC

Explanation:

The initial charge stored on the capacitor is given by:

Q=CV (1)

where

C=25 pF = 25\cdot 10^{-12}F is the capacitance of the capacitor

V=100 V is the potential difference across the capacitor

Substituting numbers into the equation, we have

Q=(25\cdot 10^{-12} F)(100 V)=25\cdot 10^{-10}C=2.5 nC

When the Teflon slab is inserted between the plates, the capacitance of the capacitor is increased as follows:

C'=kC

where k=2.1 is the dielectric constant of the Teflon. Since the voltage V remains constant, this means that the new charge stored by the capacitor (1) will be

Q'=C'V=kCV=kQ

and so

Q'=(2.1)(2.5 nC)=5.3 nC

6 0
3 years ago
Two bar magnets are placed side by side.
Jobisdone [24]

The question is wrongly written

Explanation:

There isn't a question in this.

But hope this helps

Magnets have two poles on positive and one negative

Positive and negative attract each other

3 0
4 years ago
A concave mirror produces four times magnified image of ab object placed at 10 cm in front of the mirror. find the position of i
Julli [10]

Answer:

40 cm

Explanation:

We are given that

Magnification of concave mirror, m=4

Object distance, u=-10cm

We have to find the position of image.

We know that

Magnification of concave mirror, m=-\frac{v}{u}

Using the formula

4=-\frac{v}{-10}

4=\frac{v}{10}

v=4\times 10

v=40cm

Hence, the image is formed at distance 40 cm behind the mirror.

7 0
3 years ago
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