<h2>Answer </h2>
<h3>1) iron </h3>
<h3>2) Aluminium </h3>
<h3>3) sliver </h3>
<h3>4) copper </h3>
I hope it's helpful for you ☺️
A) 8.11 m/s
For a satellite orbiting around an asteroid, the centripetal force is provided by the gravitational attraction between the satellite and the asteroid:

where
m is the satellite's mass
v is the speed
R is the radius of the asteroide
h is the altitude of the satellite
G is the gravitational constant
M is the mass of the asteroid
Solving the equation for v, we find

where:




Substituting into the formula,

B) 11.47 m/s
The escape speed of an object from the surface of a planet/asteroid is given by

where:




Substituting into the formula, we find:

Answer:
4th of August is the
Explanation:
5th and then I can help out by getting
Answer:
gravity & inertia
Explanation:
what goes up must come down & an object in motion will stay in motion until stopped
Answer:
P=I^2*R=400R where R is the resistance of the wire
Explanation: