Answer:
g(x) = -2|x+1| -3
Step-by-step explanation:
f(x) = |x|
y = f(x) + C C < 0 moves it down
y = |x| -3 for shifting down 3
y = f(x + C) C > 0 moves it left
y = |x+1| -3 for move it left 1
y = Cf(x) C > 1 stretches it in the y-direction
y = 2|x+1| -3 to stretch it 2 vertically
y = −f(x) Reflects it about x-axis
y = -2|x+1| -3
Answer:
19.5
Step-by-step explanation:
Answer:
88
Step-by-step explanation:
i am smart like that jkjk idk the answer but i think u can just google the answer and it will probably me somewheree
the answer is 75 :)) I worked it out
<h3>
Answer: Choice A) </h3>
No, the piecewise graph is NOT a function because it does NOT pass the vertical line test.
The vertical line test is where we try to pass a line through more than one point on the curve. If it is not possible to do this, then the graph is said to "pass the vertical line test".
In this case, the given graph fails the vertical line test. Look at something like x = -2. We can draw a vertical line through here to pass through more than one point. One point is on the upside-down V shape, and the other point is on the parabolic shape. Plugging x = -2 into this leads to more than one y outputs.
A function is only possible if any valid x input (from the domain) leads to exactly one output y value (in the range).
