220= 45*x. I hope you are satisfied with my answer.
I think thats what you mean hope it helps
Given:
In an asteroid field, 75% of the asteroids are carbonaceous asteroids.
There are 375,000 carbonaceous asteroids in the asteroid field.
To find:
The number of asteroids that are not carbonaceous.
Solution:
Let the total number of asteroids be x.
According to question,
![75\%\text{ of }x = 375000](https://tex.z-dn.net/?f=75%5C%25%5Ctext%7B%20of%20%7Dx%20%3D%20375000)
![\dfrac{75}{100}x=375000](https://tex.z-dn.net/?f=%5Cdfrac%7B75%7D%7B100%7Dx%3D375000)
![0.75x=375000](https://tex.z-dn.net/?f=0.75x%3D375000)
Divide both sides by 0.75.
![x=\dfrac{375000}{0.75}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B375000%7D%7B0.75%7D)
![x=500000](https://tex.z-dn.net/?f=x%3D500000)
Asteroids not carbonaceous = Total asteroids - Carbonaceous asteroids
![=500000-375000](https://tex.z-dn.net/?f=%3D500000-375000)
![=125000](https://tex.z-dn.net/?f=%3D125000)
Therefore, 125,000 asteroids are not carbonaceous.
Answer:
-11
Step-by-step explanation:
-3-(-2)+(-10)
Two - make a pos -3+2+(-10)
-1+(-10)
-11
Answer:
A. 67
B. f(4) = 42
E. f(every two odd #s) = next term
Hope this helps :)
Step-by-step explanation: