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3 years ago

7

A(n) acid is an acid that can leave solution and enter the atmosphere. a(n) acid is an acid that can leave sol

ution and enter the atmosphere. volatile fixed metabolic respiratory inorganic

1 answer:

Aneli [31]3 years ago

7 0

A volatile acid is an acid that can leave solution and enter the atmosphere.

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I have these orgo problems for homework and I have no idea where to even begin. We have to find missing reagents and products ba

almond37 [142]

Answer:

Honestly makes no sense sorry :(

Explanation:

I can try though.. There are three types of selectivity possible for any synthesis: (i) Chemoselectivity is deciding which group reacts. (ii) Regioselectivity is where the reaction takes place in that group. (iii) Stereoselectivity is how the group reacts with respect to the stereochemistry of the product.

A stereospecific mechanism specifies the stereochemical outcome of a given reactant, whereas a stereoselective reaction selects products from those made available by the same, non-specific mechanism acting on a given reactant. Of stereoisomeric reactants, each behaves in its own specific way.

I tried to explain it the best I could.

Hopefully this helps you :)

Feel free to correct me If it was wrong

5 0

3 years ago

According to the equation, 2 H2 + O2 --> 2 H20, how many moles of oxygen are required to convert 12 moles of hydrogen to wate

DerKrebs [107]

Answer:

6 moles of oxygen, or 3O2.

Explanation:

I would build a proportion for this:

$\frac{2(2)}{2} = \frac{12}{x} \\ 4x = 24 \\ x = 6$

5 0

3 years ago

A mixture of CuSO4 · 5H2O and MgSO4 · 7H2O is heated until all the water is lost. If 5.127 g of the mixture gives 2.817 g of the

Nadusha1986 [10]

Answer:

Let the mixture is X% by mass of CuSO

4

.5H

2

O and 100 - X % by mass of MgSO

4

.7H

2

O. 5.0 g of mixture will contain 0.05X g CuSO

4

.5H

2

O and 5.0 - 0.05X g MgSO

4

.7H

2

O

The molar masses of CuSO

4

.5H

2

O and MgSO

4

.7H

2

O are 249.7 g/mol and 246.5 g/mol respectively.

The number of moles of CuSO

4

.5H

2

O=

249.7

0.05X

=2.00×10

−4

X moles.

Explanation:

Pls mark it as branliest answere thanks

3 0

3 years ago

Please help with these questions ASAP will give brainlist!! CHEMISTRY

Irina18 [472]

Answer:

Question 1 is 21.0g

Explanation:

50 x 4.18 x 3.1 / 0.444 / 69.6= 21.0

4 0

3 years ago

Consider the molecules: scl2, f2, cs2, cf4, and brcl. select the choice where the bonds of the molecules are arranged in order o

elena-s [515]

The polarity of a bond depends on the difference in electronegativities of the atoms involved in bonding. Greater this difference, greater is the polarity

1) In SCl2 we have the S-Cl bond

Electronegativity values: S = 2.5, Cl = 3

Difference = 3.0 -2.5 = 0.5

2) In F2 we have the F-F bond

Electronegativity value: F = 4.0

Difference = 4.0-4.0 = 0

3) In CS2 we have the C-S bond

Electronegativity value: C = 2.5, S = 2.5

Difference = 2.5 -2.5 = 0

4) In CF4 we have the C-F bond

Electronegativity values: C = 2.5, F = 4.0

Difference = 4.0 -2.5 = 1.5

5) In BrCl we have the Br-Cl bond

Electronegativity values: Br = 2.8, Cl = 3

Difference = 3.0 -2.8 = 0.2

Therefore, the increasing order of polarity is

F2 = CS2 < BrCl < SCl2 < CF4

5 0

3 years ago