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3 years ago

TUL

Chemistry

1 answer:

wariber [46]3 years ago

5 0

Answer:

The volume of the gas will not change because the metal can is limiting it

Explanation:

Insead, Gay-Lussac's law tells us that the pressure will increase with the temprature unil the can eventually explodes, then allowing the volume to rapidly increase.

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How many neutrons are in Cesium-130 (Cs)? 55 75 130 185

11111nata11111 [884]

There is 55 neutrons in Cesium-130.

8 0

2 years ago

How many grams of solid nickel will be plated if an aqueous nickel(II) sulfate solution is electroplated over 10.5 min with a co

Anna71 [15]

Answer:

613 mg

Explanation:

$Ni^{2+} + 2e \rightarrow Ni(s)$

Number of fargday's $=\frac{It}{96500}$

Here, I = 9.20 A

t = 10.5 min

= 10.5 x 60 seconds

So, $\frac{It}{96500}$

$=\frac{3.20 \times 10.5 \times 60}{96500}$

= 0.0208 F

Here, 2e, 2F

2F = 1 mol of Ni

$0.0208 \ F = \frac{0.0208}{2} = 0.0104 \ mol \ Ni$

1 mol = 59 gm of Ni

0.0104 mol = 59 x0.0104 gm Ni

= 0.613 gm Ni

= (0.613 x 1000 ) mg of Ni

= 613 mg of Ni

3 0

2 years ago

Pu is a nuclear waste byproduct with a half-life of 24,000 y. What fraction of the 239Pu present today will be present in 1000 y

olya-2409 [2.1K]

Answer:

0.9715 Fraction of Pu-239 will be remain after 1000 years.

Explanation:

$\lambda =\frac{0.693}{t_{\frac{1}{2}}}$

$A=A_o\times e^{-\lambda t}$

Where:

$\lambda$ = decay constant

$A_o$ =concentration left after time t

$t_{\frac{1}{2}}$ = Half life of the sample

Half life of Pu-239 = $t_{\frac{1}{2}}=24,000 y$ [

$\lambda =\frac{0.693}{24,000 y}=2.8875\times 10^{-5} y^{-1]$

Let us say amount present of Pu-239 today = $A_o=x$

A = ?

$A=x\times e^{-2.8875\times 10^{-5} y^{-1]\times 1000 y}$

$A=0.9715\times x$

$\frac{A}{A_0}=\frac{A}{x}=0.9715$

0.9715 Fraction of Pu-239 will be remain after 1000 years.

7 0

2 years ago

What volume of a 0.295 M nitric acid solution is required to neutralize 24.8 mL of a 0.107 M potassium hydroxide solution

KengaRu [80]

Answer: 9.00 mL

Explanation:

$M_{A}V_{A}=M_{B}V_{B}\\(0.295)V_{A}=(0.107)(24.8)\\V_{A}=\frac{(0.107)(24.8)}{(0.295)} \approx \boxed{9.00 \text{ mL}}$

4 0

1 year ago

Heroin was originally going to be called "wunderlich", a German word for wonderful, since one chemist thought the substance made

Zarrin [17]

Answer:

heroic

Explanation:

Bayer, a German pharmaceutical company, named the substance it synthesized "heroin", probably from the word heroisch, German for heroic, because in field studies people using the medicine felt "heroic".

BTW, I found this information on this wedsite: https://www.answers.com/Q/Where_did_heroin_get_its_name

Also, if you want some more history about this drug, you can visit this article: https://www.narconon.org/drug-information/heroin-history.html

5 0

3 years ago