Rate law for the given 2nd order reaction is:
Rate = k[a]2
Given data:
rate constant k = 0.150 m-1s-1
initial concentration, [a] = 0.250 M
reaction time, t = 5.00 min = 5.00 min * 60 s/s = 300 s
To determine:
Concentration at time t = 300 s i.e. ![[a]_{t}](https://tex.z-dn.net/?f=%5Ba%5D_%7Bt%7D)
Calculations:
The second order rate equation is:
![1/[a]_{t} = kt +1/[a]](https://tex.z-dn.net/?f=1%2F%5Ba%5D_%7Bt%7D%20%3D%20kt%20%2B1%2F%5Ba%5D)
substituting for k,t and [a] we get:
1/[a]t = 0.150 M-1s-1 * 300 s + 1/[0.250]M
1/[a]t = 49 M-1
[a]t = 1/49 M-1 = 0.0204 M
Hence the concentration of 'a' after t = 5min is 0.020 M
To make 1 Molar solution of hemoglobin ; 1600 grams of hemoglobin will be dissolved in 1 liter of water
The molecular weight of Hemoglobin is approximately 16,000 Daltons, when hemoglobin is converted to mM
16000 Dalton = 16000 ( g/mol )
given that 1 Dalton = 1 g/mol
To make 1 molar solution of hemoglobin using 1 liter of water
1 liter = 1000 grams
16000 Dalton = 16000 g/mol
Hence 16,000 grams of Hemoglobin is required to make 1 Molar solution of hemoglobin using 1 liter of water.
learn more : brainly.com/question/23517096
Answer:
18.5 years
Explanation:
(6 x 10^23)/(10^15 x 1.03 x 3600 x 24 x 365)
Hope this helps!
7 valance electrons and a atomic number of 9
