Answer:
Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment, in which he demonstrated that the atom has a tiny, high- mass nucleus. In his experiment, Rutherford observed that many alpha particles were deflected at small angles while others were reflected back to the alpha source.
Answer:
the answer to your question is B
Answer:
From least polar covalent to most polar covalent;
S-I< Br-Cl < N-H< Te-O
From most ionic to least ionic
Cs-F> Sr-Cl> Li- N> Al-O
Explanation:
Electro negativity is the ability of an atom in a bonding situation to attract the electron pair of a bond towards itself.
Electro negativity difference between two atoms determines the nature of bond existing between any two atoms. When this difference is large, an ionic bond exists in the compound. However, an intermediate difference in electro negativity implies the existence of a polar covalent bond.
Hence, going by electro negativity differences as mentioned in the question, the bonds in the answer were arranged in order of increasing polar covalent nature or decreasing ionic nature as shown.
The ionic charge of oxygen is -2.
Hope this helps! ;)
Answer:
8 moles of C
Explanation:
From the question given above, the following equation was obtained:
3A + 2B —> 6C
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Thus, the number of mole of C produced by reacting 4 moles of A can be obtained as follow:
From the equation above,
3 moles of A reacted to produce 6 moles of C.
Therefore, 4 moles of C will react to produce = (4 × 6)/3 = 8 moles of C
Thus, 8 moles of C can be obtained from the reaction of 4 moles of A with excess B
