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Nostrana [21]
2 years ago
9

Please help me lol a lil confused

Mathematics
2 answers:
AnnyKZ [126]2 years ago
7 0

Answer:

3rd option is correct

Step-by-step explanation:

hope this helps you :)

alex41 [277]2 years ago
3 0

\leadsto f( \rm x) =  - (x - 3)(x - 5)

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}  - 5x - 3x + 15) \\

\\  \\

\leadsto f( \rm x) =   - ( {x}^{2}   - 8x + 15) \\

\\  \\

\leadsto f( \rm x) =   - {x}^{2}  + 8x  -  15 \\

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Step-by-step explanation:

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The slope of the tangent line to the curve x^3y+y^2-x^2=5 at the point (2,1) is
zheka24 [161]

Answer:

-4/5

Step-by-step explanation:

To find the slope of the tangent to the equation at any point we must differentiate the equation.

x^3y+y^2-x^2=5

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x^3y'+2yy'=2x-3x^2y

Factor left side

y'(x^3+2y)=2x-3x^2y

Divide both sides by (x^3+2y)

y'=(2x-3x^2y)/(x^3+2y)

y' is the slope any tangent to the given equation at point (x,y).

Plug in (2,1):

y'=(2(2)-3(2)^2(1))/((2)^3+2(1))

Simplify:

y'=(4-12)/(8+2)

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5 0
3 years ago
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Answer:

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XP=RY                                               given
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