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2 years ago

Please help me lol a lil confused

Mathematics

2 answers:

AnnyKZ [126]2 years ago

7 0

Answer:

3rd option is correct

Step-by-step explanation:

hope this helps you :)

alex41 [277]2 years ago

3 0

$\leadsto f( \rm x) = - (x - 3)(x - 5)$

$\\ \\$

$\leadsto f( \rm x) = - ( {x}^{2} - 5x - 3x + 15) \\$

$\\ \\$

$\leadsto f( \rm x) = - ( {x}^{2} - 8x + 15) \\$

$\\ \\$

$\leadsto f( \rm x) = - {x}^{2} + 8x - 15 \\$

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How to solve this one step inequality

dem82 [27]

Answer: add 1 to both sides

-1+r+1≥4+1

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x≥5

Step-by-step explanation:

8 0

3 years ago

Simplify 10p4

Ivan

10P4 = 10! / (10-4)! = 10*9*8*7 = 5040

9C4 = 9! / 5! 4! = 9*8*7*6 / 4*3*2*1 = 126

8 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided.

shutvik [7]

Answer:

Step-by-step explanation:

we are given

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

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(B)

Domain:

Firstly, we will find domain of f(x) , g(x) and (fxg)(x)

and then we can find common domain

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we know that f(x) is undefined at x=0

so, domain will be

∪

Domain of g(x):

Since, it is polynomial

so, it is defined for all real values of x

now, we can find common domain

so, domain will be

∪..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

Range of f(x):

we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

so, range is

∪

Range of g(x):

Since, it is quadratic equation

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6 0

3 years ago

2(x-6)+5=-5<br>75=27+3(3t-2)<br>-2/3(6c-9)+x=-18

anyanavicka [17]

Answer:

{c = 25/4

{t = 6

{x = 1

Step-by-step explanation:

Solve the following system:

{2 (x - 6) + 5 = -5 | (equation 1)

{75 = 3 (3 t - 2) + 27 | (equation 2)

{x - 2/3 (6 c - 9) = -18 | (equation 3)

Express the system in standard form:

{0 c+0 t+2 x = 2 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

{-(4 c) + 0 t+x = -24 | (equation 3)

Swap equation 1 with equation 3:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c - 9 t+0 x = -54 | (equation 2)

0 c+0 t+2 x = 2 | (equation 3)

Divide equation 2 by -9:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+2 x = 2 | (equation 3)

Divide equation 3 by 2:

{-(4 c) + 0 t+x = -24 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Subtract equation 3 from equation 1:

{-(4 c)+0 t+0 x = -25 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Divide equation 1 by -4:

{c+0 t+0 x = 25/4 | (equation 1)

{0 c+t+0 x = 6 | (equation 2)

{0 c+0 t+x = 1 | (equation 3)

Collect results:

Answer: {c = 25/4

{t = 6

{x = 1

4 0

3 years ago

A girl is twice as old as her sister. Five years hence, the product of their ages (in years) will be 375. Find their present age

Orlov [11]

Answer: girls=20, sister=10

Step-by-step explanation:

Let x = the girl's sister's age (present)

Let 2x= the girl's age (present)

-------------------------------------------------------------

According to the question

(x+5)(2x+5)=375

Expand parentheses by FOIL (First Outer Inner Last)

2x²+5x+10x+25=375

Combine like term (5x and 10x)

2x²+15x+25=375

Subtract 375 on both sides

2x²+15x+25-375=375-375

2x²+15x-350=0

Find the factors (cross factor)

(x-10)(x+17.5)=0

x=10 or x=-17.5 (rej) ⇔ the age can't be negative

the girl's age is 20, and her sister's age is 10.

7 0

3 years ago