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2 years ago

Solve the equation. 6^3r = 36

Mathematics

2 answers:

Hoochie [10]2 years ago

8 0

Answer:

r = 2/3

Step-by-step explanation:

$6^{3r} =36$

if:

$36=6^{2}$

$6^{3r} =6^{2}$

then:

$3r=2$

$r=2/3$

Hope this helps

Degger [83]2 years ago

5 0

Answer:

$r=\frac{2}{3}$

Step-by-step explanation:

$6^{3r}=36\\\\log_6(6^{3r})=log_6(36)\\\\3r=2\\\\r=\frac{2}{3}$

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valina [46]

Answer:

$\displaystyle T'( 2,4)$

$\displaystyle U'( 1,1)$

$\displaystyle S' ( 3,2)$

Step-by-step explanation:

we current vertices of the given triangle

$\displaystyle T( - 2,4)$
$\displaystyle U( - 1,1)$
$\displaystyle S ( - 3,2)$

remember that,

$\rm\displaystyle(x,y) \xrightarrow{ \rm reflection \: over \: y - axis}( - x,y)$

so we obtain:

$\rm\displaystyle \: T( - 2,4) \xrightarrow{ \rm reflection \: over \: y - axis}T'( 2,4)$

$\rm\displaystyle \: U( - 1,1) \xrightarrow{ \rm reflection \: over \: y - axis}U' ( 1,1)$

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2 years ago

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Lubov Fominskaja [6]

Answer:

There is no exponential function passing through (1,1) and (5,5).

Step-by-step explanation:

We have the following exponential function

$y = Ce^{kt}$

The function passes through these two points:

(1,1): This means that when t = 1, y = 1

(5,5): This means that when t = 5, y = 5.

(1,1)

$y = Ce^{kt}$

$Ce^{k} = 1$

$e^{k} = \frac{1}{C}$

(5,5)

$y = Ce^{kt}$

$5Ce^{k} = 1$

$Ce^{k} = \frac{1}{5}$

From above, we have that:

$e^{k} = \frac{1}{C}$

$C\frac{1}{C} = \frac{1}{5}$

$1 = \frac{1}{5}$

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Alexxandr [17]

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A scuba diver is swimming 15 feet below the water’s surface. The diver swims up slowly at 0.5 feet per second for 4 seconds; and

STatiana [176]

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levacccp [35]

Answer:

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Making the equation only valid for

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3 years ago