Complete question :
A heavy rainstorm dumps 1.0 cm of rain on a city 5 km wide and 8 km long in a 2-h period. How many metric tons (1 metric ton = 103 kg) of water fell on the city? (1 cm3 of water has a mass of 1 g = 10−3 kg.) How many gallons of water was this?
Answer:
4 * 10^5 metric tonne
Step-by-step explanation:
Given that :
City dimension : 5km by 8km = 5*10^5 by 8*10^5 cm
Drop of rain = 1cm
Volume of rain within 2 hour period :
V = (5*10^5 * 8*10^5 * 1) cm³
V = 40 * 10^10 cm³
1cm³ = 1g
40 * 10^10 cm³ = 40 g
(40 * 10^10) * (10^-3) = 40*10^7 kg
1 metric tonne = 1 * 10^3 kg
x = 40*10^7 kg
x = (40 * 10^7) / 10^3
x = 40 * 10^(7 - 3) metric tonne
x = 40 * 10^4
x = 4 * 10^5 metric tonne
Answer:
19
Step-by-step explanation:
Number of crackers that can be fit into the box = volume of the box / volume of crackers
Volume = length x width x height
volume of the box = 8 cm x 2.4 cm x 60 cm = 1152 cm^3
Volume of the crackers = 3cm x 4 cm x 5cm = 60cm^3
1152/60 = 19.2
Rounding 19.2 to the nearest whole number gives 19
Answer: Only A and B
Step-by-step explanation:
opposite vertical angles are made by two intersecting lines
Answer:
um could you transkate to english so i can answer your question?
Step-by-step explanation:
The domain is [0,4], as the x-values go from 0 to 4.
The range is [0,4], as the y-values span from 0 to 4.
The relation is a function
- For a relation to be a function, each x-value can have only one, distinct y-value. This is the case for this relation, as each x-input has only one corresponding y output.