KOH is a strong base and HBr is a strong acid and completely dissociates.
The balanced equation for the reaction is;
KOH + HBr ---> KBr + H₂O
Stoichiometry of acid to base is 1:1
The number of KOH moles reacted - 0.50 M / 1000 mL/L x 48.0 mL = 0.024 mol
number of HBr moles reacted - 0.25 M/ 1000 mL/L x 96.0 mL = 0.024 mol
the number of H⁺ ions are equal to number of OH⁻ ions.
Then the solution is neutral.
pH of neutral solutions at 25 °C is 7.
Therefore pH is 7
Protons are Positively charged
Electrons are Negatively charged
Electrons are attracted to Protons
C) Electron
Hope this Helps!!!
Answer:
The empirical formula=CHO. To explain it is C1H1O1 but we don't put the one that's why it is CHO
Explanation:
- See charge on ion is -1 .
Hence it has taken 1 electron
Now first look at EC of Fluorine(F)
- Now one electron added .hence no of electrons is 10now
Look at the EC
Or
![\\ \bull\sf\dashrightarrow [He]](https://tex.z-dn.net/?f=%5C%5C%20%5Cbull%5Csf%5Cdashrightarrow%20%5BHe%5D)
Option C is correct.
