Oxidation state of I is (-1) and for CO it is zero. Let's assume that the oxidation state of Fe in Fe(CO)₄I₂<span> (s) is x. For whole compound, the charge is zero.
Sum of oxidation numbers in all elements = Charge of the compound.
Here we have 1Fe , 4CO and 2I
hence we can find the oxidation state as;
x + 4*0 + 2*(-1) = 0
x + 0 - 2 = 0
x = +2
Hence the oxidation state of Fe in product </span>Fe(CO)₄I₂ (s) is +2.
Same as we can find the oxidation state (y) of Fe in Fe(CO)₅(s).
y + 5*0 = 0
y = 0
Since oxidation state of Fe increased from 0 to +2, the oxidized element is Fe in the given reaction.
J. J. Thomson is the corect awncer
Answer:
because the tectonic plates move 4 inches per year.
Explanation:
Answer:
Density rectangular block = 7.47 (Approx) gm/cm³
Explanation:
Given:
Length = 8.335 cm
Width = 1.02 cm
Height = 0.982 cm
Mass = 62.3538 gm
Find:
Density rectangular block
Computation:
Volume of block = lbh
Volume of block = (8.335)(1.02)(0.982)
Volume of block = 8.3486 cm³
Density = Mass / Volume
Density rectangular block = 62.3538 / 8.3486
Density rectangular block = 7.47 (Approx) gm/cm³
Answer:
Common ones are Gasoline, Diesel fuel, and Kerosene.
Explanation:
Many accelerants are hydrocarbon-based fuels, sometimes referred to as petroleum distillates: gasoline, diesel fuel, kerosene, turpentine, butane, and various other flammable solvents. These accelerants are also known as ignitable liquids. Ignitable liquids can leave behind tell-tale marks in the fire debris.
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