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kobusy [5.1K]
3 years ago
6

At 25.0∘c, the molar solubility of barium chromate in water is 1.10×10−5 m . calculate the solubility in grams per liter.

Chemistry
1 answer:
Masja [62]3 years ago
6 0
When in water, barium chromate dissociates into ions. The dissociation equation would be as follows:

<span>BaCrO4 = Ba^2+ + CrO4^2+
</span>
For this case, we are to convert only from moles per kg to grams per liter. We do as follows:

<span>1.10×10^−5 mol / kg ( 253.37 g /mol) ( 1 kg/L ) = 2.79x10^-3 kg / L = 2.79 g/L</span>
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<h3>HOW TO CALCULATE NUMBER OF MOLES?</h3>

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