Question

At 25.0∘c, the molar solubility of barium chromate in water is 1.10×10−5 m . calculate the solubility in grams per liter.

Answer 1

When in water, barium chromate dissociates into ions. The dissociation equation would be as follows:

BaCrO4 = Ba^2+ + CrO4^2+

For this case, we are to convert only from moles per kg to grams per liter. We do as follows:

1.10×10^−5 mol / kg ( 253.37 g /mol) ( 1 kg/L ) = 2.79x10^-3 kg / L = 2.79 g/L