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2 years ago

At 25.0∘c, the molar solubility of barium chromate in water is 1.10×10−5 m . calculate the solubility in grams per liter.

1 answer:

6 0

When in water, barium chromate dissociates into ions. The dissociation equation would be as follows:

BaCrO4 = Ba^2+ + CrO4^2+

For this case, we are to convert only from moles per kg to grams per liter. We do as follows:

1.10×10^−5 mol / kg ( 253.37 g /mol) ( 1 kg/L ) = 2.79x10^-3 kg / L = 2.79 g/L

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Ipatiy [6.2K]

Your answer should be “C.”

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6 0

3 years ago

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Arrange the following molecules according to the strength of their dispersion forces. Organize in order from largest to smallest

ki77a [65]

Explanation:

The weak intermolecular forces which can arise either between nucleus and electrons or between electron-electron are known as dispersion forces. These forces are also known as London dispersion forces and these are temporary in nature.

Therefore, more is the surface area occupied by the carbon chain more will be the dispersion forces present in it. Hence, less is the surface area occupied by a molecule less will be the dispersion forces present in it.

Hence, the given molecules are organized from largest to smallest dispersion forces as follows.

$CH_{3}CH(CH_{3})C(CH_{3})_{2}CH_{2}CH_{3}$ > $CH_{3}CH_{2}(CH_{2})_{4}CH_{2}CH_{3}$ > $CH_{3}CH_{2}CH_{2}CH_{2}CH_{3}$ > $CH_{3}C(CH_{3})2CH_{3}$ > $CH_{3}CH_{2}CH_{3}$ > $CH4$

3 0

2 years ago

Consider the reaction 2NO(g) 1 O2(g) ¡ 2NO2(g) Suppose that at a particular moment during the reaction nitric oxide (NO) is reac

GalinKa [24]

<h2>a) The rate at which $NO_2$ is formed is 0.066 M/s</h2><h2>b) The rate at which molecular oxygen $O_2$ is reacting is 0.033 M/s</h2>

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2NO(g)+O_2(g)\rightarrow 2NO_2(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of $NO$ = $-\frac{1d[NO]}{2dt}$ = 0.066 M/s

Rate in terms of disappearance of $O_2$ = $-\frac{1d[O_2]}{dt}$

Rate in terms of appearance of $NO_2$ = $\frac{1d[NO_2]}{2dt}$

1. The rate of formation of $NO_2$

$-\frac{d[NO_2]}{2dt}=\frac{1d[NO]}{2dt}$

$\frac{1d[NO_2]}{dt}=\frac{2}{2}\times 0.066M/s=0.066M/s$

2. The rate of disappearance of $O_2$

$-\frac{1d[O_2]}{dt}=\frac{d[NO]}{2dt}$

$-\frac{1d[O_2]}{dt}=\frac{1}{2}\times 0.066M/s=0.033M/s$

Learn more about rate law

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7 0

3 years ago

The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. what is its mo

Semenov [28]

Knowing the ratio between atoms we can write an empirical formula:

C4H6O 

we compute the molar mass of this single formula: 
4x12 + 6 x 1 + 16 x1 = 70 g / mol 

Now, as we know the actual molar mas being 280 g/mol, we divide this number by 70 and we get the ratio between empirical formula and molecular actual formula: 

280 / 70 = 4 

This means that actual molecular formula is: 

(C4H6O)4 or 

C16H24O4

3 0

2 years ago

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This is due at 12am HELP!!

Lisa [10]

Answer:

I have the same

Explanation:

like I have the same homework as you are u in my class lol?

4 0

2 years ago