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Margarita [4]
3 years ago
12

B) calculate the ratio of moles of h2o to moles of anhydrous kal(so4)2. note: report the ratio to the closest whole number. (sho

w all work including units)
Chemistry
1 answer:
Sindrei [870]3 years ago
5 0

Answer: -

Mass of Hydrated KAl(SO₄)₂ = 2.0 g

Molar mass of anhydrous KAl(SO₄)₂ = 258.20 g/ mol

Mass of of anhydrous KAl(SO₄)₂ = mass of the 2nd heating = A

The mass of water released = mass of the Aluminum Cup + 2.0 grams of KAl(SO₄)₂ - mass of the 2nd heating

= H g

Moles of water released = \frac{H g}{18 g/mol}

Moles of anhydrous KAl(SO₄)₂ = \frac{A g}{258.20 g/mol}

Required ratio = \frac{moles of water}{moles of anhydrous KAl(SO4)2}

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