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Gennadij [26K]
4 years ago
8

Which of the following statements best predicts the pH value of H2CO3 and KOH?

Chemistry
1 answer:
worty [1.4K]4 years ago
4 0

Answer:

The 2nd one

Explanation:

ITS THE RIGHT ANSWER

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. Mitosis allows one cell to grow and split into 2 new cells. Will those 2 new cells split again explain.
Finger [1]

Answer:

Yes

Explanation:

They continue to split and grow and split again until the organism that is carrying them dies.

Sorry I don't really know how to explain:(

4 0
3 years ago
Please help me with this question please!!!
Deffense [45]

Answer:

A

Explanation:

I looked up aromatic hydrocarbon and this one looks like a replica of benzene

3 0
3 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
3 years ago
Draw the curved arrows to show the mechanism for the reaction of butanedioic (succinic) anhydride with methanol.
Marta_Voda [28]
Here is the mechanism of said reaction.

8 0
4 years ago
8. The standard enthalpy of formation of RbF(s) is –557.7kJ/mol and the standard enthalpy of formation of RbF(aq, 1 m) is –583.8
garri49 [273]

Explanation:

Given

The enthalpy of formation of RbF (s) is –557.7kJ/mol

The standard enthalpy of formation of RbF (aq, 1 m) is –583.8 kJ/mol

The enthalpy of solution of RbF = Enthalpy of RbF (aq) - Enthalpy of formation of RbF (s)

= -583.8 - (-557.7)  kJ/mol

= -26.1 kJ/mol

The enthalpy is negative which means that the temperature will rise when RbF is dissolved.

3 0
3 years ago
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