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Thepotemich [5.8K]
3 years ago
15

Sodium bicarbonate (baking soda), NaHCO,, can be purified by dissolving it in

Chemistry
2 answers:
torisob [31]3 years ago
6 0

Answer:

the other person is right

Explanation:

they're also wrong

DochEvi [55]3 years ago
5 0

Answer:

58% or 55.34%

Explanati

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What is the formula for the ionic compound of strontium and chlorine?
Leno4ka [110]
The formula is SrCl2. hope this helps
8 0
4 years ago
A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to
grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0
4 years ago
If 5.0 mL of a Sports Drink with an absorbance reading of 0.34 was diluted with water to 10.0 mL and was read by the colorimeter
MaRussiya [10]

Answer:

the expected absorbance of the solution = 0.17

Explanation:

From the information given:

Using Beer's Lambert Law, we have

A = ∈CL

where;

A = Absorbance

∈ = extinction coefficient

C = concentration

L = cell length

Since Absorbance is associated with concentration.

Assuming the measurement were carried out in the same solution; Then  ∈ and L will be constant and A  ∝ C ----- (1)

Let consider the concentration to be C  (mol/L)

5.0 mL of a Sports Drink = 5.0 mL × C (mol)/1000 mL

= 5C/1000 mL

was diluted with water to 10.0 mL

So, when diluted with water to 10.0 mL; we have:

The new concentration to be : \dfrac{(5 C \times 1000) \ mol }{(1000 \times 10 \times 1000)\  mL}

Since :1000mL = 1 L

The new concentration = \dfrac{C \ mol }{2 \ L}

As stated that the initial absorbance reading A_1 = 0.34

The expected absorbance reading will be A_2 = ???

From (1)

A ∝ C

∴

\dfrac{A_2}{A_1}=\dfrac{C_2}{C}

A_2 = \dfrac{A_1}{C}

A_2 = \dfrac{0.34}{2}

A_2 = 0.17

Thus ; the expected absorbance of the solution = 0.17

8 0
3 years ago
The three naturally occurring isotopes of potassium are 39K, 38.963707u; 40K, 39.963999u; and 41K.The percent natural abundances
sweet-ann [11.9K]

Answer:

The isotopic mass of 41K is 40.9574 amu

Explanation:

Step 1: Data given

The isotopes are:  

39K with an isotopic mass of 38.963707u and natural abundance of 93.2581%

40K with an isotopic mass of 39.963999u

41K wit natural abundance of 6.7302 %

Average atomic mass =39.098 amu  

Step 2: Calculate natural abundance of 40 K

100 % - 93.2581 % - 6.7302 %

100 % = 0.0117 %

Step 3: Calculate isotopic mass of 41K

39.098 = 38.963707 * 0.932581 + 39.963999 * 0.000117 + X * 0.067302

39.098 = 36.33681 + 0.0046758 +  X * 2.067302

X = 40.9574 amu

The isotopic mass of 41K is 40.9574 amu

8 0
4 years ago
12. (06.01 MC)
qaws [65]

Answer:

Elastic collisions between gas particles: Ideal gases are assumed to interact via perfectly elastic collisions in which no energy is lost. Intermolecular forces describe the attraction and repulsion between particles. They include: Instantaneous dipole-induced dipole forces or London dispersion forces.

Explanation:

7 0
3 years ago
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