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kow [346]
3 years ago
10

During an experiment, 575 mL of neon gas at 101 kPa were compressed in a cylinder to a volume of 144 mL.

Chemistry
1 answer:
Ne4ueva [31]3 years ago
8 0

Answer:

403.3 kPa is the new pressure

Explanation:

This problem is solved by this formula:

P₁ . V₁ = P₂ . V₂

101kPa . 575 mL = P₂ . 144mL

(101kPa . 575 mL) / 144 mL = P₂

403.3 kPa = P₂

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Answer:

The answer B is correct

Explanation:

The answer B is correct

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3 years ago
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1) A 10g sample of H2(g) reacts with a 22g sample of O2(g) according to
solmaris [256]

Answer:

H₂ is excess reactant and O₂ the limiting reactant

Explanation:

Based on the chemical reaction:

2H₂(g) + O₂(g) → 2H₂O

<em>2 moles of H₂ react per mole of O₂</em>

<em />

To find limiting reactant we need to convert the mass of each reactant to moles:

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<em>Moles O₂ -Molar mass: 32g/mol-:</em>

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For a complete reaction of 0.69 moles of O₂ are needed:

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As there are 4.96 moles,

<h3>H₂ is excess reactant and O₂ the limiting reactant</h3>
7 0
4 years ago
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3 years ago
A curium-245 nucleus is hit with a neutron and changes as shown by the equation. Complete the equation by filling in the missing
Lera25 [3.4K]

Try this option:

^{245}_{96}Cm+^1_0n=^{103}_{42}Mo+^{245+1-103-3*1}_{96+0-42-3*0}(X)+3^1_0n;

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