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larisa [96]
2 years ago
12

Evaluate 8.1p + 7.9r when p=7 and r=8

Mathematics
1 answer:
Ivenika [448]2 years ago
8 0

Answer:

119.9

Step-by-step explanation:

(8.1)(7)+(7.9)(8)

(8.1)(7)+(7.9)(8)

=119.9

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A coordinate grid is placed over a map and every unit represents 1 mi. The point at (3, 8) represents the location of the baseba
alexira [117]
The distance between 2 points ( x_{1}, y_{1}) and ( x_{2}, y_{2}) on the coordinate plane is \sqrt{(x_{2}-x_{1})^2-(y_{2}-y_{1})^2}
So the distance between the given points is \sqrt{(7-3)^2+(-2-8})^2}= \sqrt{4^2+(-10)^2}= \sqrt{16+100}=  \sqrt{116}=10.8
As every unit is 1 mile, so the distance should be 10.8*1=10.8miles.

Hope this helps.
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4 years ago
Please help due tommorow
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Answer:

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Step-by-step explanation:

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In this lesson, you worked with composite functions. Now make up any two functions f(x) and g(x), defined in terms of the variab
yaroslaw [1]
There are g(f(x)) and f(g(x))
do them then evaluate

lets say
f(x)=3x
g(x)=9x^3-4

g(f(x))=9(3x)^3-4=243x^3-4
f(g(x))=3(9x^3-4)=27x^3-12
we can see that g(f(x)) with yield a higher value for x=10

4 0
3 years ago
What is the volume of the composite figure? A rectangular prism is positioned vertically; at the top it joins another rectangula
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V = V 1 + V 2 + V 3 =
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5 0
4 years ago
James wants to compete in the international speed texting competition next year where participants compete on text speed and acc
lions [1.4K]

Complete question :

James wants to compete in the international speed texting competition next year where participants compete on text speed and accuracy. James’s current text speed is 2 characters per second. James has found that his texting speed increases at a rate of 1⁄2 a character per second for each month that he practices.

1. a. What is James’s new texting speed if he practices for only 1 month? __________

b. What is James’s new texting speed if he practices for 2 months? ____________

c. What is his new texting speed if he practices for 3 months? _____________

d. Write an algebraic equation that gives James’s texting speed s for m months of

practice.

Answer:

2 1/2 ; 3, 3 1/2 ; s = 2 + 1/2m

Step-by-step explanation:

Given that :

Speed = 2 characters per second

Rate of change = 1/2 character per second increase per month

New texting speed after 1 month :

Initial speed + (change per month * number of months)

2 + 1/2 * 1

= 2 1/2 or 2.5

After 2 months :

Initial speed + (change per month * number of months)

2 + (1/2 * 2)

2 + 1

= 3 characters per second :

After 3 months :

Initial speed + (change per month * number of months)

2 + 1/2 * 3

= 2 + 1.5

= 3.5

For the algebraic equation :

New texting speed, s

Number of months, m

Initial speed + (change per month * number of months)

s = 2 + 1/2 * m

s = 2 + 1/2m

4 0
3 years ago
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