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2 years ago

Which number is not equal to one of the following expressions? 1,400 x 10

Mathematics

1 answer:

pochemuha2 years ago

8 0

The answer is 140

Explanation:
1,400 x 10= 14,000
140,000\100=1,400
1,400 x 100= 140,000

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Solve for d:<br> d+(−5.004)=2.826 <br> Include explanation on how you got your answer :)

aleksklad [387]

Answer:

$d = 7 .83$

Step-by-step explanation:

1. Remove parentheses.

$d + - 5.004 = 2.826$

2. Simplify d + -5.004 to d - 5.004.

$d - 5.004 = 5.004$

3. Add 5.004 to both sides.

$d = 2.826 + 5.004$

4. simplify 2.826 + 5.004 to 7.83.

$d = 7.83$

Therefor, rhe answer is D = 7.83

8 0

3 years ago

I came up the answer as 57. I will attach my note, can you check?

ololo11 [35]

BC=19

Explanation

Step 1

ABE

triangle ABE is rigth triangle, then let

$\begin{gathered} Angle=60 \\ adjacentside=BE \\ opposit\text{ side(the one in front of the angle)= AB=}\frac{19\sqrt[]{6}}{4} \end{gathered}$

so, we need a function that relates, angle, adjancent side and opposite side

$\tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}}$

replace

$\begin{gathered} \tan \theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan 60=\frac{AB}{\text{BE}} \\ \text{cross multiply} \\ \text{BE}\cdot\tan \text{ 60=AB} \\ \text{divide both sides by tan 60} \\ \frac{\text{BE}\cdot\tan\text{ 60}}{\tan\text{ 60}}=\frac{\text{AB}}{\tan\text{ 60}} \\ BE=\frac{\text{AB}}{\tan\text{ 60}} \\ \text{if AB=}\frac{19\sqrt[]{6}}{4} \\ BE=\frac{\frac{19\sqrt[]{6}}{4}}{\sqrt[]{3}} \\ BE=\frac{19\sqrt[]{6}}{4\sqrt[]{3}} \end{gathered}$

Step 2

BED

again, we have a rigth triangle,then let

$\begin{gathered} \text{Hypotenuse}=BD \\ \text{adjacent side= BE=6.71} \\ \text{angle}=\text{ 45} \end{gathered}$

so, we need a function that relates; angle, hypotenuse and adjacent side

$\cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}}$

replace.

$\begin{gathered} \cos \theta=\frac{adjacent\text{ side}}{\text{hypotenuse}} \\ \cos 45=\frac{6.71}{\text{BD}} \\ BD=\frac{6.71}{\cos \text{ 45}} \\ BD=\frac{\frac{19\sqrt[]{6}}{4\sqrt[]{3}}}{\frac{\sqrt[]{2}}{2}} \\ BD=\frac{38\sqrt[]{6}}{4\sqrt[]{6}} \\ BD=\frac{38}{4} \end{gathered}$

Step 3

finally BDE

let

angle=30

opposite side= BD

use sin function

$\begin{gathered} \sin \theta=\frac{opposite\text{ side}}{\text{hypotenuse}} \\ \text{replace} \\ \sin \text{ 30=}\frac{BD}{BC} \\ BC\cdot\sin 30=BD \\ BC=\frac{BD}{\sin \text{ 30}} \\ BC=\frac{\frac{38}{4}}{\frac{1}{2}} \\ BC=\frac{76}{4}=19 \\ BC=19 \end{gathered}$

so, the answer is 19

I hop