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Butoxors [25]
3 years ago
5

A rancher has 400 feet of fencing to put around a rectangular field and then subdivide the field into 3 identical smaller rectan

gular plots by placing two fences parallel to one of the field's shorter sides. Find the dimensions that maximize the enclosed area.
Mathematics
1 answer:
MAXImum [283]3 years ago
5 0

Answer:

longer parallel sides are 150ft each with 4 shorter sides at 25ft each making a rectangle and 3 identical sections.

Step-by-step explanation:

150 + 150 = 300

4 ×25 = 100

300+100=400

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Answer:

(3, -4)

Step-by-step explanation:

Lines are intersecting at points (3, -4).

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4 0
3 years ago
Question 1
Ilia_Sergeevich [38]

We will see that the perimeter of the rectangle is exactly 390 ft, so the statement is true.

<h3>Is the fence enough?</h3>

For a rectangle of length L and width W, the perimeter is given by:

P = 2*(L + W).

In this case, we know that:

L = 120 ft

W = 75 ft

Replacing that on the perimeter equation we get:

P = 2*(120 ft + 75  ft) = 390 ft

So the perimeter is exactly 390 ft, meaning that to put a fence around the parking lot the company will need at least 390 ft of fence.

So the statement is correct.

If you want to learn more about perimeters, you can read:

brainly.com/question/24571594

4 0
2 years ago
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sergij07 [2.7K]
The answer is y=\frac{10}{3} Hope this helps
3 0
3 years ago
Help me plzzz with my math
Kipish [7]

Answer:

The answer is A.

Step-by-step explanation:

Hope this helped! :)

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3 years ago
How do I simplify this??
alina1380 [7]
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