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2 years ago

What the answer? find the value of x

Mathematics

1 answer:

Agata [3.3K]2 years ago

8 0

Answer:

x=5

Step-by-step explanation:

The line goes through the point (5,7) which is when y=7 so x=5

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Tell whether each pair of angles are elther supplementary or congruent.

sveta [45]

It’s supplementary
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3 years ago

the sum of two numbers is 123. when the larger number is added to 5 times the smaller, the sum is 343. find the numbers.

vovikov84 [41]

Create a system of equations
x + y = 123
5x + y = 343

I use substitution
y = 123 - x
5x + 123 - x = 343
4x + 123 = 343
4x = 220
x = 55

Plug in
x + y = 123
55 + y = 123
y = 68

Check
5x + y = 343
5(55) + 68 = 343
275 + 68 = 343
343 = 343

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2 years ago

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the instructor has save $3500 and rents an apartment for $275 monthly. he believes the point 6, 1850 would be on the equation of

bazaltina [42]

Answer:Yes, he is correct

Step-by-step explanation:Plug 6 in as your x-value in the equation y=-275x+3500 and you will get y=1850

6 0

3 years ago

Does anyone know how to do this, i’ll give you brainliest and there’s 16 points

leva [86]

6y-4=4y+2

2y=6, so y=3.

Plugging it in, you get that AC equals 4*3+2=14.

This is an isosceles triangle.

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3 years ago

Expand a logarithmic expression

ivanzaharov [21]

The logarithmic expression is

$log (\sqrt{z^5}/(x^3y))$

To expand the expression we have to use some properties of logarithm.

We know that $log(m/n) = log (m) - log(n)$

By using this property we can write,

$log(\sqrt{z^5}) - log(x^3y)$

Square root means to the power 1/2, so for $\sqrt{z^5}$ , we can write $z^(5/2)$ .

$log(z^(5/2)) - log(x^3y)$

Now we have to use another property of logarithm.

We know that, $log(mn) = log(m) + log(n)$

So we will use this property to $log(x^3y)$

$log(z^(5/2)) - log(x^3y)$

$log(z^(5/2)) - (log(x^3) + log(y))$

$log(z^(5/2)) - log(x^3) - log(y)$

Now we have to use another property of logarithm.

We know that, $log(a^m) = m log(a)$

By using this property we can write,

$(5/2)log(z) - 3log(x) - log(y)$

This is the required aswer here.

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4 years ago

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