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2 years ago

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What is the actual length of the living space if the length of the scale drawing is 16. 8 centimeters? Enter your answer in the

box.

1 answer:

yaroslaw [1]2 years ago

7 0

To solve the problem we must know about the Ratio.

<h2>What is Ratio?</h2>

A ratio shows us the number of times a number contains another number.

The length of the living space, in reality, is 21 meters.

Given to us

The scale is given as 2 centimeters equals 2.5 meters.

To find

the actual length of the living space if the length of the scale drawing is 16. 8 centimeters

<h3>Scale ratio</h3>

As it is given that 2 cm on the scale drawing is equal to 2.5 meters in real, therefore, the ratio can be written as

$\dfrac{\text{Length of the scale drawing}}{\text{Length in reality}} = \dfrac{2\ cm}{2.5\ meters}$

<h3>Length of the living space</h3>

Using the same scale ratio,

$\dfrac{\text{Length of the living space in scale drawing}}{\text{Length of the living space in reality}} = \dfrac{2\ cm}{2.5\ meters}$

$\dfrac{16.8}{x} = \dfrac{2\ cm}{2.5\ meters}\\\\x=\dfrac{16.8 \times 2.5}{2} = 21\ meters$

Hence, the length of the living space, in reality, is 21 meters.

Learn more about Ratio:

brainly.com/question/1504221

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Step-by-step explanation:

The system of hypothesis on this case are:

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Alternative hypothesis: $\mu_1 \neq \mu_2$

Or equivalently:

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Alternative hypothesis: $\mu_1 -\mu_2\neq 0$

Our notation on this case :

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$n_2 =5$ represent the sample size for group 2

We can calculate the mean and deviation for eaach group with the following formulas:

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$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}$

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