Answer:
Solution given:
f(x)=x²
g(x)=x+5
h(x)=4x-6
now
23:
(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25
24:
(gof)(x)=g(f(x))=g(x²)=x²+5
25:
(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36
26:
(hof)(x)=h(f(x))=h(x²)=4x²-6
27;
(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1
28:
(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14
The answer is 10 because it’s multiplies by 10
Answer: d) v = 3.20 + 1.50n.
Step-by-step explanation:
Let 'v' be the price to pay in a 'n' kilometer.
Given: The price to be paid for a taxi ride includes a fixed parcel, called a flag, and a parcel that depends on the distance traveled.
Flag costs = $ 3.20 and
Each kilometre run costs = $ 1.50
Then, the amount of 'v' to pay in a 'n' kilometer race = Flag costs + (n)× (Each kilometre run costs )
⇒ v= 3.20 + 1.50n
Hence, the correct option is d) v = 3.20 + 1.50n.
Answer:
c i think sorry if i get it wrong
Step-by-step explanation:
Answer:
Here look at this graph this is your answer.
