T = tension force in the rope in upward direction
m = mass of the box attached at end of rope = 56 kg
W = weight of the box in downward direction due to gravity
a = acceleration of the box in upward direction = 5.10 m/s²
weight of the box is given as
W = mg
inserting the values
W = (56) (9.8)
W = 548.8 N
force equation for the motion of the box is given as
T - W = ma
inserting the values
T - 548.8 = (56) (5.10)
T = 834.4 N
The problem was too big to type in my phone.
I hope my answer is readable.
P.S After the collision P is also moving in the same direction as Q.
Answer:
The velocity of the other fragment immediately following the explosion is v .
Explanation:
Given :
Mass of original shell , m .
Velocity of shell , + v .
Now , the particle explodes into two half parts , i.e
.
Since , no eternal force is applied in the particle .
Therefore , its momentum will be conserved .
So , Final momentum = Initial momentum

The velocity of the other fragment immediately following the explosion is v .
Since the angle is West of North, therefore to find for
the westward component (horizontal component) of the vector, we use the sin
function:
sin θ = opposite side / hypotenuse = westward component /
resultant vector
So the westward component (x) is:
x = 85.42 sin 23
<span>x = 33.38 unit</span>