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Blizzard [7]
3 years ago
13

A shell of mass m and speed v explodes into two identical fragments. If the shell was moving horizontally (the positive x direct

ion) with respect to Earth, and one of the fragments is subsequently moving vertically with speed v, find the velocity ' of the other fragment immediately following the explosion. (Use the following as necessary: v.)
Physics
1 answer:
-Dominant- [34]3 years ago
4 0

Answer:

The velocity of the other fragment immediately following the explosion is v .

Explanation:

Given :

Mass of original shell , m .

Velocity of shell , + v .

Now , the particle explodes into two half parts , i.e  \dfrac{m}{2} .

Since , no eternal force is applied in the particle .

Therefore , its momentum will be conserved .

So , Final momentum = Initial momentum

mv=\dfrac{mv}{2}+\dfrac{mu}{2}\\\\u=v

The velocity of the other fragment immediately following the explosion is v .

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The ___ of an object measures the amount of matter in t g e object
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I believe it is the mass of an object. The question is oddly asked
4 0
4 years ago
The Problems: 1. Xavier starts at a position of 0 m and moves with an average speed of 0.50 m/s for 3.0 seconds. He normally mov
NemiM [27]

Answer:

(1). His final position is 1.5 m.

(2). The final position of the hedgehog is 3 m.

(3). The final position of the tortoise

(4). Her race time is 80 sec.

(5). It take to finish in 5 hr.

Explanation:

(1). Given that,

Initial position = 0 m

Average speed = 0.50 m/s

Time = 3.0 s

We need to calculate the final position

Using formula of average speed

v_{av}=\dfrac{x_{f}+x_{i}}{t}

Where, x_{f} = final position

x_{i} = Initial position

t = total time

Put the value into the formula

0.50=\dfrac{x_{f}+0}{3.0}

x_{f}=0.50\times3.0

x_{f}=1.5\ m

(2). Given that,

Initial position = 0 m

Average speed = 0.75 m/s

Time = 4.0 s

We need to calculate the final position

Using formula of average speed

v_{av}=\dfrac{x_{f}+x_{i}}{t}

Put the value into the formula

0.75=\dfrac{x_{f}+0}{4.0}

x_{f}=0.75\times4.0

x_{f}=3\ m

(3). Given that,

Average speed = 1.25 m/s

Time = 3.0 sec

Initial position = 1.0 m

We need to calculate the final position

Using formula of average speed

v=\dfrac{x_{f}+x_{i}}{t}

Put the value into the formula

1.25=\dfrac{x_{f}+1.0}{3.0}

x_{f}=1.25\times3.0-1.0

x_{f}=2.75\ m

(4). Given that,

Average speed = 1.25 m/s

Distance = 100 m

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{100}{1.25}

t=80 sec

(5). Given that,

Average speed = 5 miles/hr

Suppose, distance = 25 miles

We need to calculate the time

Using formula of time

t=\dfrac{d}{v}

Put the value into the formula

t=\dfrac{25}{5}

t=5\ hr

Hence, (1). His final position is 1.5 m.

(2). The final position of the hedgehog is 3 m.

(3). The final position of the tortoise

(4). Her race time is 80 sec.

(5). It take to finish in 5 hr.

5 0
4 years ago
A 15 kg bowling ball is moving at 5m/s down the bowling lane, calculate its<br> momentum
Tanzania [10]
75 kg/m/s^2. Momentum = mass x velocity
6 0
3 years ago
Read 2 more answers
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
Sunny_sXe [5.5K]

Answer:

a) 5.09 seconds

b) 107.07 meters

Explanation:

a) As we know

t_2- t_1 = \sqrt{\frac{2 X}{a} }

Substituting the given values we get

t_2 - t_1 = \sqrt{\frac{2 * 52}{4} } \\t_2 - t_1 = 5.09

It takes 5 .09 s for the motorcycle to accelerate until it catches up with the car

b)

X_{t`2} = v_i \sqrt{\frac{2X}{a} } + 0.5 a\sqrt{\frac{2X}{a} }\\X_{t`2} =  (v_i + 0.5 a) \sqrt{\frac{2X}{a} }\\X_{t`2} =  ( 19 + 2)  \sqrt{\frac{2* 52}{4} }\\X_{t`2} =  21 * 5.09\\X_{t`2} = 107.07

4 0
3 years ago
What is the maximum mass of ethyl alcohol you could boil with 2000 j of heat, starting from 19 ∘c?
RSB [31]
The boiling point of ethanol is at 78.37°C. So, the energy must include sensible heat to raise 19°C to the boiling point and latent heat to change liquid to gas. The equation would be

Energy = Sensible heat + Latent heat
Energy = mCpΔT + mΔH

For ethanol, 
Cp = 46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ J/kmol·K
ΔH = 38,560 J/mol

Integrate the Cp expression to determine CpΔT:

CpΔT = ∫₂₉₂³⁵²(46.068 + 102,460T - 139.63T² - 0.030341T³ + 0.0020386T⁴ )dT
The upper limit is (78.37+273) = 352 K, while the lower limit is (19 + 273) = 292.
CpΔT = 2384857192 J/kmol·K

2,000 J = m(2384857192 J/kmol)(1 kmol/1000 mol) + m(38,560 J/mol)
m = 8.253×10⁻⁴ moles of ethanol
Since the molar mass of ethanol is 46.07 g/mol,
Mass = (8.253×10⁻⁴ mol)(46.07 g/mol)
Mass = 0.038 g ethanol
8 0
4 years ago
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