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garik1379 [7]
3 years ago
11

ABCD is a plane quadrilateral and E is any point on AD. EF is drawn parallel to DB to meet AB in F, and EG is drawn parallel to

DC to meet AC in G. Prove that F G is parallel to BC. solution
Mathematics
1 answer:
JulsSmile [24]3 years ago
5 0
UMMMMM just add ab plus f divide gggggggggggggggggg and add 666666666666666666666666666666666666666666666666666666666666666666666666666666666666
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Use compatible numbers to estimate the quotient 2,545÷4
victus00 [196]

Answer:

600

Step-by-step explanation:

round 2,545 to 2,400 and keep 4 the same because 24 goes into 4 six times so 2400/4 equals 600  

24/4 is 6 and you add the two zeros

3 0
3 years ago
Which expression is equivalent to 150x² - 60x ?
Bas_tet [7]

Answer: The Answer is B

Step-by-step explanation:

You need to distribute 15x(10x - 4). 15x times 10x is 150x and since there is 2 x's your gonna square it. So then it would be 150x². next 15x times -4 is -60 and add your x. Your answer is 150x² - 60x.

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3 years ago
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Which one A, B, C, or D
rjkz [21]

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The answer would be A

8 0
3 years ago
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If I sent out 200 letters and got 80 responses. If I want 20 more responses how many more letters do I have to send out
yawa3891 [41]

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Step-by-step explanation:

50

7 0
3 years ago
a pool is being filled with a large water hose. the height of the water in a pool is determined by 7g^2+3g-4. Previously the poo
ArbitrLikvidat [17]

If both the hoses are on the same time then the height of the water in the pool is given by the expression  15g^2 + 5g - 6

Step-by-step explanation:

(7g^2 + 3g - 4) + (8g^2 + 2g - 2)

= (7g^2 + 8g^2) + ( 3g + 2g) + (-4 -2)

with the help of distribution law,

= (7 +8)g^2 + (3 + 2)g - (4 + 2)

= 15g^2 + 5g - 6

Therefore if both the hoses are on the same time then the height of the water in the pool is given by the expression  15g^2 + 5g - 6

3 0
3 years ago
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