ABCD is a plane quadrilateral and E is any point on AD. EF is drawn parallel to DB to meet AB in F, and EG is drawn parallel to
1 answer:
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We have two solutions for this problem based on the given equation.
<u><em>Answer #1:</em></u>
<u>If the given equation was:</u>
To solve for f, we would need to isolate the "f" on one side of the equation.
In case of the above equation, we can simply do that by subtracting from both sides of the equation
<u>This would give:</u>
f + -
= 6 -
f = 6 -
<u><em>Answer #2:</em></u>
<u>If the given equation was:</u>
To solve for f, we would still need to isolate the "f" on one side of the equation.
<u>This can be done as follows:</u>
................> multiply both sides by (g)
f + 4 = 6g ................> subtract 4 from both sides of the equation
f + 4 - 4 = 6g - 4
f = 6g - 4
Hope this helps :)
Answer:
or -6.122
Step-by-step explanation:
In answering this kind of questions, you must take note of BODMAS. that is;
B - Bracket
O - Of (multiplication)
D - Division
M - Multiplication
A - Addition
S - Subtraction
and you have to answer by the order above to get the correct answer. thank you
hope it helps .