There are 6 letters, each different
Before MOTHER, words from E , H will come
Words from E = 5! (there are 5 letters to arrange)
Words from H = 5!( there are 5 letters to arrange)
Now words starting by M will come.
First ME will have = 4! (as 4 letters will be arranged)
Then MH = 4!
Now words with MO<span>
</span><span>First words starting with MOE... =3!
And words starting with MOH... =3!
the words starting with MOR... =3!
Now, words starting from MOT will come
words starting with MOTE.. = 2!
then after words starting from MOTH will come and first word will MOTHER
so, total no. of words before MOTHER = 5! + 5! + 2* 4! + 3 * 3!
= 120 +120 + 48 + 18
= 306
so, rank of MOTHER = 307</span>
Answer:
Table F
Step-by-step explanation:
The equation is C = 0.75t. The variable c is for cost and t is for tickets. When we use substitution to solve the equation, we see that table F correctly represents the situation. In simpler terms, the equation is asking us to mutliply the cost PER ticket by the number of tickets.
0.75 * 1 = 0.75
0.75 * 2 = 1.50
0.75 * 3 = 2.25
0.75 * 4 = 3
And so on. As we can see, the only table that shows these values is in fact table F.
Hope this helps!
The answer would be 303.62 if I’m not mistaken
The answer to this question is 5589
Answer:
B. 3/9 = 4/12 = 1/3
Step-by-step explanation:
I calculated it logically
