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dem82 [27]
3 years ago
10

..................plz solve

Mathematics
2 answers:
Alinara [238K]3 years ago
3 0

Answer: K= 5

Step-by-step explanation: Hope this helps! :)

ZanzabumX [31]3 years ago
3 0

Answer:

K = 5 ( I need 20 words)

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Please Help!
Deffense [45]

Answer:

12

Step-by-step explanation:

7 0
3 years ago
Find the value of x in each case.
prisoha [69]
It’s 282 because if you add all those rhe divide you get the answer
3 0
3 years ago
What is the result of converting 6 inches into centimeters
svetlana [45]

The conversion rate is 1 inch = 2.54 cm. So for this, we will have to multiply 6 times 2.54 to get the length in centimeters.

6 x 2.54 = 15.24

6 inches equals 15.24 cm.

Hope that helps!

5 0
4 years ago
Jackson mows 1/3 of his neighbors lawn in 1/6 of an hour. At this rate, how many lawns of the same size could he mow in one hour
IrinaK [193]
He could mow 2 lawns. if he mows 1/3 of the law in 1/6 of an hour, then he can mow 2/3 of the law in 2/6 of an hour. keep adding 1/3 to the amount of lawn mowed as you add 1/6 to the amount of hours, until you hit 6/6 hours, which would be one hour
7 0
3 years ago
How would I solve this
Tresset [83]
Recall your d = rt, or distance = rate * time

the two planes, are 1180 miles apart
say plane A and plane B

two hours later, they pass each other
how long have both been flying by the time they passed each other?
well, 2 hrs
so the time for both is the same, 2

now, one is faster than the other, by 4 miles, say hmmm plane A, doesn't really matter, it could be either... but say A, so if A has a rate of "r",
B will have a rate of r-4, whatever "r" is

now, the distances travelled, say A travelled distance "d", whatever that is,
B, travelled the difference from 1180 and that, or 1180 - d
1180 is the total amount of miles apart, take away "d", and B travelled
1180 - d

thus \bf \begin{array}{rccclll}
&distance&rate&time(hrs)\\
&-----&-----&-----\\
\textit{first plane}&d&r&2\\
\textit{second plane}&1180-d&r-4&2
\end{array}
\\\\\\
thus\implies 
\begin{cases}
\boxed{d}=(r)(2)\\\\
1180-d=(r-4)(2)\\
--------------\\\\
1180-\boxed{(r)(2)}=(r-4)(2)
\end{cases}

solve for "r", to see A's rate

how fast was B going? well, r-4
4 0
3 years ago
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