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raketka [301]
3 years ago
9

D = 18 in. Fine the radius or diameter of each circle with the given dimensions. ​

Mathematics
1 answer:
Alborosie3 years ago
4 0

Answer:

r= 9

Step-by-step explanation:

radius (r) = diameter (D)/2

= 18/2

= 9

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Refer to the various selling prices of various homes in a community that follow the normal distribution with mu (population mean
blsea [12.9K]

Answer:

0.43715

Step-by-step explanation:

We solve using z score calculator

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = $276,000

σ is the population standard deviation = 32,000

For x = $276,000

z = 276,000 - 276,000/32000

z = 0

Probability value from Z-Table:

P(x = 276000) = 0.5

For x = $325,000

z = 325,000 - 276,000/32000

z = 1.53125

Probability value from Z-Table:

P(x = 325000) = 0.93715

The probability that the next house in the community will sell for between $276,000 and $325,000 is

P(x = 325000) - P(x = 276000)

= 0.93715 - 0.5

= 0.43715

8 0
3 years ago
If the sample variance for a frequency distribution consisting of hourly wages was computed to be 10, what is the sample standar
skad [1K]

The sample standard deviation is (B) $3.16.

<h3>What is the sample standard deviation?</h3>
  • The sample standard deviation is defined as the root-mean-square of the differences between observations and the sample mean: A significant deviation is defined as two or more standard deviations from the mean.
  • The lowercase Greek letter (sigma) for the population standard deviation or the Latin letter s for the sample standard deviation is most commonly used in mathematical texts and equations to represent standard deviation.
  • For example, if the sample variance for a frequency distribution of hourly wages is 10 and the sample standard deviation is $3.16.

Therefore, the sample standard deviation is (B) $3.16.

Know more about sample standard deviation here:

brainly.com/question/475676


#SPJ4

The complete question is given below:
If the sample variance for a frequency distribution consisting of hourly wages was computed to be 10, what is the sample standard deviation?

A. $4.67

B. $3.16

C. $1.96

D. $10.00

7 0
2 years ago
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
Evaluate.
aleksandrvk [35]

Answer: -2 4/15

Step-by-step explanation: To properly subtract, we need to find a common denominator. We can list the multiples of 3 and 5 to find the common denominator:

3: 3, 6, 9, 12, 15

5: 5, 10, 15


The first common multiple we see is 15.

Calculation:

3 · 3 = 9

9 + 1 = 10

3 1/3 = 10/3

5 x 5 = 25

25 + 3 = 28

-5 3/5 = -28/5

Now to convert into fifteen as the denominator:

-28/5 = -28 x 3/5 x 3 = -84/15

10/3 = 10 x 5/3 x 5 = 50/15

Now to subtract accordingly:

50/15 - 84/15 = -34/15

Final answer: -34/15 (can be reduced to -2 4/15).

3 0
1 year ago
What 0.5628 rounded to nearest hundred​
konstantin123 [22]

Answer:

0.56

Step-by-step explanation:

5 0
3 years ago
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