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2 years ago

9

Antonio has been learning to draw landscapes. It has been hard at times but he is happy about the progress he has made. What is

this an example of?
solution

problem

advice

d.challenge

'

1 answer:

Diano4ka-milaya [45]2 years ago

6 0

The answer to your question is going to be challenge

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Before setting your prices, it's wise to

Dima020 [189]

"research industry standards" is the answer i believe

4 0

3 years ago

Read 2 more answers

he company rented an office for $ 3600 per month starting from January 1, 2018. On that day, ABC prepaid the rent through June

pickupchik [31]

Answer:

The balance in the Prepaid Rent account as of April 30, 2018 = $7,200

Explanation:

Monthly rent = $3,600

Rent paid on 1 January = $3,600 $\times$ 6 = $21,600

Out of which Prepaid Rent = $3,600 $\times$ 5 = $18,000

for 5 months

Prepaid rent account as on April 30 balance will be of rent for May and June,

That is $3,600 $\times$ 2 = $7,200

Only this amount will be outstanding in prepaid rent as for the month till April each month rent would have been adjusted from February to April.

Final Answer

The balance in the Prepaid Rent account as of April 30, 2018 = $7,200

8 0

3 years ago

Sheffield Corporation exchanged 2750 shares of Pharoah Company common stock, which Sheffield was holding as an investment, for e

AveGali [126]

Answer: Please refer to Explanation

Explanation:

When recording Equipment here the value of the shares at current value should be used and not the cost of the equipment.

DR Equipment $162,250

CR Investment in Pharaoh Company $137,500

CR Gain on Exchange $24,750

(To record Exchange of shares for Equipment)

Workings.

Investment in Pharaoh Company.

= 2,750 shares * $50(purchase price)

= $137,500

Gain on Exchange

= 2,750 shares * (Market Price - Purchase Price)

= 2,750 shares * ( 59 - 50)

= $24,750

Equipment.

= Investment in Pharoah Company + Gain on Exchange

= 137,500 + 24,750

= $162,250

6 0

3 years ago

Computing second-year depreciation and accumulated depreciationAt the beginning of 2016, Air Asia purchased a used airplane at a

Bezzdna [24]

Answer:

1. a.$4,375,000

b. $7,500,000

c. $9,800,000

2. $8,750,000

$18,200,000

$17,500,000

Explanation:

1. The computation of the depreciation expense for the second year is presented below:

a) Straight-line method:

= (Purchase value of airplane - residual value) ÷ (useful life)

= ($40,000,000 - $5,000,000) ÷ (8 years)

= ($35,000,000) ÷ (8 years)

= $4,375,000

In this method, the depreciation is same for all the remaining useful life

(b) Double-declining balance method:

First we have to find the depreciation rate which is shown below:

= One ÷ useful life

= 1 ÷ 8

= 12.5%

Now the rate is double So, 25%

In year 1, the original cost is $40,000,000 so the depreciation is $10,000,000 after applying the 25% depreciation rate

And, in year 2, the $30,000,000 × 25% = $7,500,000

(c) Units-of-production method:

= (Purchase value of airplane - residual value) ÷ (estimated miles)

= ($40,000,000 - $5,000,000) ÷ ($5,000,000 miles)

= ($35,000,000) ÷ ($5,000,000 miles)

= $7 per miles

In first year, it would be

= Miles in first year × depreciation per miles

= 1,200,000 miles × $7

= $8,400,000

Now for the second year, it would be

= Miles in second year × depreciation per miles

= 1,400,000 miles × $7

= $9,800,000

2. The calculation of the accumulated depreciation balance would be

Straight line method:

= $4,375,000 + $4,375,000

= $8,750,000

Double-declining balance method:

= $10,000,000 + $7,500,000

= $17,500,000

Units-of-production method:

= $8,400,000 + $9,800,000

= $18,200,000

4 0

3 years ago

If a student attends every management science class, the probability of passing the course is 0.80; but if the student only atte

goldfiish [28.3K]

Answer:

EV of node 4 = 0.6×5 + 0.4×0 = 3

EV of node 5 = 0.1×5 + 0.9×0 = 0.5

EV of node 2 = (0.8×5 + 0.2×EV of node 4) - 3

EV of node 2 = (0.8×5 + 0.2×3 ) - 3

EV of node 2 = 4.6 - 3

EV of node 2 = 1.6

EV of node 3 = (0.5×5 + 0.5×EV of node 5) - 1

EV of node 3 = (0.5×5 + 0.5×0.5 ) - 1

EV of node 3 = 2.75 - 1

EV of node 3 = 1.75

EV of node 3 is higher, therefore, best attend pattern is to attend randomly.

4 0

3 years ago