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2 years ago

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2 answers:

Arte-miy333 [17]2 years ago

8 0

ANSWER: Volumn of cone = 130.9m³

I hope this helps you :)

const2013 [10]2 years ago

4 0

Answer:

volume for this cone is 47.1 m³

Explanation:

$\boxed{Volume -of -cone=\frac{1}{3} \pi r^2h}$

Using the formula:

$\frac{1}{3} * (3.14)* 3^2 * 5$

$\frac{1}{3} * 141.3$

$47.1$ m³

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How do I slove this eqaution, and whats the answer?<br> -3(n+6)+10=-9

Sauron [17]

Answer:

$n = \frac{1}{3}$

Step-by-step explanation:

Apply the distributed property, so it now looks like this: -3n + -18 + 10 = -9
Combine like terms: -3n + -8 = -9
Simplify: -3n - 8 = -9
Add 8 to each side, so it now looks like this: -3n = -1
Divide each side by -3 to cancel out the -3 next to n. It should now look like this: n = 1/3

I hope this helps!

8 0

3 years ago

Find the area of the unfolded box bottom.

Marysya12 [62]

The answer is 150 because
5*30
shortcut: 5*3=15
add the zero from the 50
150 is your answer..

6 0

3 years ago

What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16

kicyunya [14]

Answer:

$y=\pm i \sqrt{7}$

Step-by-step explanation:

Given equation is $\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

Factor denominators then solve by making denominators equal

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}$

$\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}$

$y\left(y+4\right)-4\left(y-4\right)=9$

$y^2+4y-4y+16=9$

$y^2=9-16$

$y^2=-7$

take squar root of both sides

$y=\pm \sqrt{-7}$

$y=\pm i \sqrt{7}$

Hence final answer is $y=\pm i \sqrt{7}$ .

7 0

3 years ago

Find the approximate perimeter of rectangle ABCD plotted below. B(4,5) AC -6,0) C(8,-3) D(-2,-8) Choose 1 answer: Do 5 problems

Likurg_2 [28]

Answer:

Perimeter of rectangle ABCD = 47.62

Step-by-step explanation:

The perimeter of a rectangle is P = 2(length + width)

You need to find length and width

If you graph, you can pick your length length and your width

Pick two points after you graph, for $(x_{1},y_{1}) and (x_{2},y_{2})$

Use the distance formula to find the length = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point B (4,5) will be point 1 and point C (8,-3) will be point 2

Substitute

length = $\sqrt{(8 - 4 )^{2} + (-3- 5 )^{2}}\\$

length = $\sqrt{80}$

length = 8.94

Use the distance formula to find the width = $\sqrt{(x_{2} - x_{1} )^{2} + (y_{2} - y_{1} ^{2})}$

point C (8,-3) will be point 1 and point D (-2,8) will be point 2

Substitute

width = $\sqrt{(-2 - 8 )^{2} + (8- (-3) )^{2}}\\$

width = $\sqrt{(-10 )^{2} + (11 )^{2}}\\$

width = $\sqrt{100 + 121}\\$

width = $\sqrt{221}$

width = 14.87

Now use formula P = 2(length + width)

P = 2(8.94 + 14.87)

Perimeter of rectangle ABCD = 47.62

7 0

3 years ago

7. Triangle FIP was dilated by a scale factor of centered at the origin to

Assoli18 [71]

Answer:

AB is parallel to A'B'.

DO,1/2 (1/2x, 1/2y) =

The distance from A' to the origin is half the distance from A to the origin.

Step-by-step explanation:

6 0

2 years ago