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3 years ago

HELP IM DESESPERATED PLSSSSSSSS ITS THE 4TH TIME I POST PLSSSSSSSS 6th GRADE MATH

Mathematics

2 answers:

Flura [38]3 years ago

7 0

Variable for all be x,y,z

Answers are

$\\ \tt\hookrightarrow 3x+8$

#2.

$\\ \tt\hookrightarrow 9x$

$\\ \tt\hookrightarrow 3x+4y+z$

Serga [27]3 years ago

6 0

Answer:

Step-by-step explanation:

Three times a number plus 8 girls would be

3x+8

The variable is x

The constant is 8

and the coefficient is 3

If Trey now has 9 times as many cards as he did when he began collecting, we can use the number of cards he had before as x.

Trey has 9x cards.

The variable in this equation is x and the constant is 9

If Nina has 3 dimes and 1 nickel in her pocket, we can say the dimes are b and the nickel is c

If she found some quarters on the ground, we can say the quarters are A, but we don't know how many, so we need x to represent how many quarters. the Variables in this equation are B, C, and A (b, c, and a)

We can write this in an equation as

3b+c +(ax) the coefficient is x, and the constant is 3

In the equation 2n+4, the variable is n, the coefficient is 4, and the constant is 2

A word problem for this equation could be:

Ray collects marbles. Ray's friend gave him 2 times as many marbles as he already had, and he found 4 marbles on the way home from his friend's house.

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One is Iraq! :) (Hope this helps!)

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Read 2 more answers

Each side length of the parallelogram at the right is multiplied by 4 describe the change into the perimeter.judtify your answer

Sloan [31]

Let's say we have a parallelogram that has sides of 2 and 3
perimeter = 2 * (side1 + side2)
perimeter = 2 * (2 + 3)
perimeter = 10

If the sides are increased by a factor 4, the sides are 8 and 12
perimeter = 2 * (side1 + side2)
perimeter = 2 * (8 + 12)
perimeter = 40

The perimeter increases by a factor 4.

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3 years ago

Can someone help me answer this, I have to find the factors of the constant, c. Find the factors of c whose sum is b. And rewrit

densk [106]

Answer:

Step-by-step explanation:

that should be the answer

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3 years ago

Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

7 0

3 years ago