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Dennis_Churaev [7]
2 years ago
13

Solve for x. please help.

Mathematics
1 answer:
exis [7]2 years ago
3 0

Please find the attached photograph for your answer

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If a new data point at 12 is added to the graph, which will be true?
love history [14]

Answer:

the answer is C on edge

7 0
3 years ago
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Is this true?
mars1129 [50]

Answer:

Yes!

Step-by-step explanation:

If you work out the opperation it is true!

(I would do it, but the numbers a really big. :D But trust me i did it and it worked. ^_^)

7 0
3 years ago
Graph triangle RST with vertices R(3, 7), S(-5, -2), and T(3, -5) and its image after a reflection over x = -3.​
kirill115 [55]

Given:

The vertices of a triangle are R(3, 7), S(-5, -2), and T(3, -5).

To find:

The vertices of the triangle after a reflection over x = -3 and plot the triangle and its image on the graph.

Solution:

If a figure reflected across the line x=a, then

(x,y)\to (-(x-a)+a,y)

(x,y)\to (-x+a+a,y)

(x,y)\to (2a-x,y)

The triangle after a reflection over x = -3. So, the rule of reflection is

(x,y)\to (2(-3)-x,y)

(x,y)\to (-6-x,y)

The vertices of triangle after reflection are

R(3,7)\to R'(-6-3,7)

R(3,7)\to R'(-9,7)

Similarly,

S(-5,-2)\to S'(-6-(-5),-2)

S(-5,-2)\to S'(-6+5,-2)

S(-5,-2)\to S'(-1,-2)

And,

T(3,-5)\to T'(-6-3,-5)

T(3,-5)\to T'(-9,-5)

Therefore, the vertices of triangle after reflection over x=-3 are R'(-9,7), S'(-1,-2) and T'(-3,-5).

3 0
3 years ago
Please answer this ASAP. The question is down below. Thank you!
Sonja [21]

Answer:

y = .5x^2 -2x -5

Step-by-step explanation:

Well we can start by seeing if the parabola is the same width by comparing it to its parent function ( y = x^2 )

In y = x^2 the 2nd lowest point is just up 1 and right 1 away from the vertex.

This is not true for our parabola.

So we can widen it by to the desidered width by making the x^2 into a .5x^2.

So far we’ve got y = .5x^2

Now the parabola y intercept is at -5.

So we can add a -5 into the equation making it.

y = .5x^2 - 5

Now for the x value.

So we can find the x value by seeing how far away the parabola is from from the y axis.

So the x value is -2x.

So the full equation is y = .5x^2 -2x -5

Look at the image below to compare.

7 0
3 years ago
Read 2 more answers
Question 11 Find the value of y. X+ 13 45° No links please! Thanks for the help!​
9966 [12]

Answer:

First option: 13 \sqrt{2}

Step-by-step explanation:

cosθ =  \frac{adj}{hyp}

cos45° =  \frac{13}{y}

Multiply both sides by y:

y(cos45°) = 13

y ( \frac{ \sqrt{2} }{2} ) = 13

y = 13 \div  \frac{ \sqrt{2} }{2}

y = 13 \times  \frac{2}{ \sqrt{2} }

y =  \frac{26}{ \sqrt{2} } ( \frac{ \sqrt{2} }{ \sqrt{2} } )

y =  \frac{26 \sqrt{2} }{2}

y = 13 \sqrt{2}

7 0
3 years ago
Read 2 more answers
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