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Gelneren [198K]
3 years ago
8

Can someone help me with graphing this function?

Mathematics
1 answer:
Paul [167]3 years ago
5 0

p.s. Excuse the scribble.

Step-by-step explanation:

This is a piece-wise function. The three intervals we need to worry about are [0, 1), [1,2], and [2,4].

Separate the functions into their pieces and draw out the individual graphs. Place them together onto the graph within their respective intervals.

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Please help.<br> Is algebra.<br> PLEASE HELP NO LINKS OR FILES.<br> I don't want links.
alexandr1967 [171]

9514 1404 393

Answer:

  9n^4

Step-by-step explanation:

The divisor and quotient can be interchanged to find the divisor:

  \dfrac{18n^6+27n^5-36n^4}{2n^2+3n-4}=\boxed{\text{Blank 1}}

Such division is carried out by first finding the quotient of the highest-degree terms:

  \dfrac{18n^6}{2n^2}=\dfrac{18}{2}n^{6-2}=9n^4

This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...

  9n^4

_____

The attachment shows the long division.

7 0
3 years ago
What is the answer to this question?
dimulka [17.4K]
It decreased $7 in the last 2 days
8 0
3 years ago
Urgent, please i will give brainliest
Ne4ueva [31]

Answer:

1. \frac{\sqrt{13} }{3}

2. 3.2362

3. \frac{60}{11}

Step-by-step explanation:

1.

Cot is the trigonometric ratio defined by "adjacent" over "opposite". <em>So, adjacent = 2 and opposite = 3.</em>

By pythagorean theorem, we have the "hypotenuse" as  \sqrt{2^2+3^2}=\sqrt{13}

Csc is defined as the trig ratio "hypotenuse" over "opposite". <em>We know the sides, so Csc \theta = \frac{\sqrt{13} }{3}</em>

<em />

<em>First answer choice is right.</em>

<em />

2.

By definition, Csc \theta is the inverse of Sine \theta. <em>If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:</em>

Csc\theta=\frac{1}{0.3090}\\=3.2362

Third answer choice is right.

3.

By definition tan and cot are inverse of each other. <em>So the value of tan is the reciprocal of the value of cot.</em> We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

Cot\theta=\frac{60}{11}

Third answer is right.

3 0
3 years ago
Read 2 more answers
Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6
Anton [14]

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

V= \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder,x^{2}+y^{2} =1 and the ellipsoid, 4x^{2}+ 4y^{2} + z^{2} =64

In polar coordinates, we know that

x^{2}+y^{2} =r^{2}

So, the ellipsoid gives

4{(x^{2}+ y^{2)} + z^{2} =64

4(r^{2}) + z^{2} = 64

z^{2} = 64- 4(r^{2})

z=± \sqrt{64-4r^{2} }

So, the volume of the solid is given by:

V= \int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta

= 2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta

To solve the integral take, 64-4r^{2} = t

dt= -8rdr

rdr = \frac{-1}{8} dt

So, the integral  \int\ r\sqrt{64-4r^{2} } rdr become

=\int\ \sqrt{t } \frac{-1}{8} dt

= \frac{-1}{12} t^{3/2}

=\frac{-1}{12} (64-4r^{2}) ^{3/2}

so on applying the limit, the volume becomes

V= 2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta

=\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta

V = \frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Since, further the integral isn't having any term of \theta.

we will end here.

The Volume of the given solid using polar coordinate is:\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0
2 years ago
Solve for x.<br> ­a = bx<br> A) (­-b)\a<br> B) b -­ a<br> C) (­-a) + b<br> D) (­-a)/b
Andreyy89
I doubt the options you've mentioned here.
The correct answer should be x=a/b
3 0
3 years ago
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