9514 1404 393
Answer:
9n^4
Step-by-step explanation:
The divisor and quotient can be interchanged to find the divisor:

Such division is carried out by first finding the quotient of the highest-degree terms:

This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...
9n^4
_____
The attachment shows the long division.
It decreased $7 in the last 2 days
Answer:
1. 
2. 3.2362
3. 
Step-by-step explanation:
1.
Cot is the trigonometric ratio defined by "adjacent" over "opposite". <em>So, adjacent = 2 and opposite = 3.</em>
By pythagorean theorem, we have the "hypotenuse" as 
Csc is defined as the trig ratio "hypotenuse" over "opposite". <em>We know the sides, so Csc
=
</em>
<em />
<em>First answer choice is right.</em>
<em />
2.
By definition, Csc
is the inverse of Sine
. <em>If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:</em>

Third answer choice is right.
3.
By definition tan and cot are inverse of each other. <em>So the value of tan is the reciprocal of the value of cot.</em> We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

Third answer is right.
The Volume of the given solid using polar coordinate is:![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
V= ![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
<h3>
What is Volume of Solid in polar coordinates?</h3>
To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.
Consider the cylinder,
and the ellipsoid, 
In polar coordinates, we know that

So, the ellipsoid gives

4(
) +
= 64
= 64- 4(
)
z=± 
So, the volume of the solid is given by:
V= ![\int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta](https://tex.z-dn.net/?f=%5Cint%5Climits%5E%7B2%5Cpi%7D_%200%20%5Cint%5Climits%5E1_0%7B%7D%20%5C%2C%20%5B%5Csqrt%7B64-4r%5E%7B2%7D%20%7D-%20%28-%5Csqrt%7B64-4r%5E%7B2%7D%20%7D%29%5D%20r%20dr%20d%5Ctheta)
= 
To solve the integral take,
= t
dt= -8rdr
rdr = 
So, the integral
become
=
= 
=
so on applying the limit, the volume becomes
V= 
=![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2864-4%281%29%5E%7B2%7D%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864-4%282%29%5E%7B0%7D%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
V = ![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
Since, further the integral isn't having any term of
.
we will end here.
The Volume of the given solid using polar coordinate is:![\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7B6%7D%20%5Cint%5Climits%5E%7B2%5Cpi%7D_%20%7B0%7D%20%5B%2860%29%20%5E%7B3%2F2%7D%20%5C%3B%20-%2864%29%20%5E%7B3%2F2%7D%20%5D%20d%5Ctheta)
Learn more about Volume in polar coordinate here:
brainly.com/question/25172004
#SPJ4
I doubt the options you've mentioned here.
The correct answer should be x=a/b