Will name BRAINLEST! Determine the area of the given triangle. *
1 answer:
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Answer:
1)4
2)28
3)18.3
4)38.5
5)22.5
6)19.25
7)25.5
8)69.666
9)6.5
10)22.666
Step-by-step explanation:
- To do this first you should convert the mix numbers into inproper fractions and then solve.
1)8/5*5/2=4
2)21/5*20/3=7*4
=28
3)33/4*20/9=11*5/3
=55/3
=18.33...
=18.3
4)35/6*33/5=7*11/2
=77/2
=38.5
5)22/8*90/11=45/2
=22.5
6)11/3*21/4=11*7/4
=77/4
=19.25
7)34/5*15/4=34*3/4
=25.5
8)22/3*57/6=11*19/3
=209/3
=69.666
9)39/8*4/3=13/2
=6.5
10)17/2*8/3=17*4/3
=68/3
=22.666
<em>Hope you got this</em>
<em>If you have any doubt please ask me</em>
<em>If you need this in fraction form just check the attachment</em>
Given equation is
The given equation is in the form of
a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
