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nikdorinn [45]
3 years ago
14

HELP ME OUT PLEASE!!!!!!​

Mathematics
2 answers:
qaws [65]3 years ago
8 0

Step-by-step explanation:

when it is phrased like that it should mean that we apply the scale factor to the original images to create the new ones.

and that means the new images will in our case be bigger by the factor of 2.

therefore, the 4th answer option is correct.

2 cm turn into 2×2 = 4 cm

1.5 cm turn into 2×1.5 = 3 cm

3 cm turn into 2×3 = 6 cm

algol [13]3 years ago
4 0

2cm turn into 2×2 = 4 cm

1.5cm turn into 2×1.5= 3 cm

3cm turn into 2×3 = 6cm

Therefore , 4th option is correct

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Decide whether or not it is a function.​
MariettaO [177]
Function because nothing repeats in the domain
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3 years ago
In a​ survey, 32​% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result
adoni [48]

Answer:

z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of  pet owners contacted by telephone is NOT significantly lower than 0.32

Step-by-step explanation:

Data given and notation

n=210 represent the random sample taken

X=61 represent the number of pet owners contacted by telephone

\hat p=\frac{61}{210}=0.29 estimated proportion of  pet owners contacted by telephone

p_o=0.32 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.32.:  

Null hypothesis:p \geq 0.32  

Alternative hypothesis:p < 0.32  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of  pet owners contacted by telephone is NOT significantly lower than 0.32

3 0
3 years ago
Y=x^2-2x-5;y=x^3-2x^2-5x-9
ehidna [41]
Are the directions asking you to solve these ?
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Answer:

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Step-by-step explanation:

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3 years ago
The amount of money in Toni's savings account after x weeks is described by the function
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The correct answer would be B, or the second option.

In a function like this, the y-intercept, or the term without a variable, can be always be interpreted as a sort of starting amount, or a base amount.

Because we're given 5x + 20, we know 20 will be the base, or starting value, while 5 is the amount being added per value of x, which is equal to weeks.

Thus, the correct answer is B.

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4 years ago
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