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3 years ago

(FIRST CORRECT FOR BRAINIEST) Solve for x

Mathematics

2 answers:

Katyanochek1 [597]3 years ago

4 0

Answer:

x = 12

Step-by-step explanation:

Angles in a triangle add up to equal 180 degrees

Hence, 10x - 11 + 3x - 2 + 3x + 1 = 180

( note that we just created an equation that we can use to solve for x )

we now solve for x using the equation we created

10x - 11 + 3x - 2 + 3x + 1 = 180

step 1 combine like terms

10 + 3x + 3x = 16x

- 11 - 2 + 1 = -12

we now have 180 = 16x - 12

step 2 add 12 to each side

- 12 + 12 cancels out

180 + 12 = 192

we now have 192 = 16x

step 3 divide each side by 16

16x / 16 = x

192 / 16 = 12

we're left with x = 12

Elena L [17]3 years ago

4 0

Answer:

x=12

the seniot math wiz already explained it correctly

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3 years ago

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djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
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Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
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Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

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