No because 5 quarts are greater than 1 quart and 3 quarts are greater than 1 quart.
Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
Answer:
y=0
Step-by-step explanation:
x y
-2 0.04
-1 0.2
0 1
1 5
2 25
Replace the f(x) in the second equation will 6x + 5 so then it looks like 2(6x + 5) + 6. Then distribute so it’s 12x + 10 + 6 and then simplify to 12x + 16