Answer:
P = 2(2y+3)
P = 30
Step-by-step explanation:
P = 2 (L+W) or P = L + L + W + W
P = 2 (2y+3)
P = 4y+6
Plug in 6 for y.
P = 24+6
P = 30
Answer:
-3, 1, 5, 9
Step-by-step explanation:
2(2) - 7 = -3
2(4) - 7 = 1
2(6) - 7 = 5
2(8) - 7 = 9
Answer:
r = 9
Step-by-step explanation:
cross multiply
9 * r = 81
9r = 81
divide both sides by 9
r= 81/9
r = 9
Well according to the slope intercept equation.
Y = mx +/- b
The slope is the value m
The y intercept is b
To graph the function, one sure way to do it is simply make a table of values picking any x values that fall within the graph space, and finding out the resulting y values and using the points to graph.
For instance for the first graph, if x = 0, y = 5, that is one possible point. Keep on choosing x values to graph.
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
