Grade 4
1 answer:
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I have included attachment below
so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2
answer is 336 m^2
so since a rhombus is 2 pairs of paralell sides, we can cut it into 4 triangles
we can see that we can take the bottom 2 triangles and put them on top to get a rectangle that is width 21 and height 32/2 (16=height
area of rectangle=legnth times width=16 times 21=336 m^2
answer is 336 m^2
Answer:
(24, 224 ) i.e. 24 basketball and 224 footballs
Step-by-step explanation:
<em>Basketball :</em>
uses 4 ounces of foam
20 minutes of labor
profit = $2.50
<em>Football :</em>
uses 3 ounces of foam
30 minutes of labor
profit = $2
Manufacturer has :
768 ounces of foam , 120 labor hours per week,
<u>using the simplex method to determine the optimal production schedule so as to maximize profits </u>
lets assume
x = number of basketball
y = number of footballs
maximize = 2.5 x + 2y from a linear programming problem
attached below is the detailed solution
The volume of cone B will be 6 cubic units.
<h3>What is the volume of the cone?</h3>Let h be the height of the cone and A be the base area of the cone.
Then the volume of the cone will be
Volume = (1/3) × A × h
Consider cone A and cone B.
The bases of the cones are congruent.
The height of cone A is 4 times larger than the height of cone B.
The volume of cone A is 24.
24 = (1/3) Ahₐ
Then the volume of the cone B will be
Simplify the expression, then the volume will be
V = 1/4 x (1/3)Ahₐ
V = 1/4 x 24
V = 6 cubic units
The volume of cone B will be 6 cubic units.
More about the volume of the cone link is given below.
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