Answer:
SSD = 565.54 ft
Explanation:
Given data:
driver speed = 60 mph
clear distance available to stop the truck on emergency can be calculated by using stopping sight distance
SSD = Lag distance + breaking distance
let take comfortable acceleration rate as a = 11.2 ft/s^2
g =32.2 ft/s^2
a = fg
speed is given as 60 mph
we know that 1 mile 5290 ft
i hr = 3600 sec
therefore v = 88 ft./s
from standard assumption time to reaction is taken as 2.5 sec
so
SSD = 565.54 ft
Answer:
R = 1 kΩ
i_L = 2.2 mA
Explanation:
The complete question is given in attachment:
Given:
- The gain i_L / i_i = 11
- Given circuit Attachment
Find:
- Find the required value of R
- If the amplifier is fed with a current source having a current of 0.2 mA and a source resistance of 10 kΩ, find iL
Solution:
- Use KVL on right most loop (load loop):
v_x = 0 - i_i*10 = -10i_i
- Using ohm's law:
i = (0 - v_x) / R
i = 10*i_i / R
- Use KCL at the node:
i_L = i + i_i
- Substitute the the two i:
i_L = 10*i_i / R + i_i
i_L / i_i = ( 10/ R + 1 )
11 = ( 10/ R + 1 )
10 / R = 10
R = 1 kΩ
- The input resistance = 0 because there is a virtual ground at input. Then the value of source resistance will have no effect on resulting i_l, hence:
i_L = i_L / i_i * i_i
i_L = 11*0.2
i_L = 2.2 mA
Answer: Yes
Explanation:
While handling and managing offices, means a lot of different tasks, including files,overseeing supplies, running the mailroom and worker productivity, the space planner work is to specifically focus on managing the space within your office building. When it comes to all room within each wing of each floor, the space planner's work is to layout and optimize the design in order to maximize productivity and also keep the employees happy.
Work of the space ePlanner includes all those in listed above in the question.
Explanation:
This is not so much a mathematical issue as a case study, because the response will inevitably require us to test the special Columbic shuttle disaster scenario. I would suggest that you read this in detail and present the points accordingly. Here I give as many points as I think are relevant.
The failure of a space program is definitely a complex situation, more than a simple binomial distribution. It's definitely not as simple as repeating the flip of a coin. There are several coherent factors and situations that govern the overall coordination and execution of such an event. The problem is, those who are running a project like this are still making a trade off,It is never the case that they sealed the lid on any chance of failure between multiple parameters. You try to do something, but often, as is the case above, the potentially dangerous situation is impossible or uncontrollable. Since the root cause of failure, which is dried out tiles that can not withstand heat and water, it appears that owing to the constant use of the shuttle the head architects have not foreseen this.
Answer: True
Explanation:Typical metals have a property of ductility and malleability that is metals can be drawn into wires or any other shape by beating or stretching the metal by putting the tensile strength or shear strength that pulls them apart . But while compression the metals are squeezed together which affects the hardness of a metal and they are not able to bear the compression force well and thus cannot show elastic-plastic behavior while compression .Therefore the statement given is true typical metals show elastic-plastic behavior in tension and shear but not in compression.